使用xmlSlurper计算XML中每个重复条目的计数

时间:2013-05-29 19:11:27

标签: xml groovy grails-2.0 xmlslurper

我必须计算XML中出现的每个无效数字(BTNumber)的外观。我正在使用groovy XmlSlurper()。请建议如何计算数量和计数(在xml中的次数)

例如 -

   BTNumber     | count
 ----------------------------------
   2205867438   |   2
   78124614     |   3

XML代码如下 -

<Results>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>2205867438
</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>2461253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:50:04.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>2205867438</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>2461253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:50:18.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>2201159526</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>1111253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:53:07.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>1011159526</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>1111253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:53:18.0</DateStamp>
</Row>
</Results>
 <Results>
  <Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>78124614</BTNumber>
    <CPNumber>78124614</CPNumber>
    <DialedNumber>7812461400</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>MyNetwork</CarrierCode>
    <DateStamp>2013-03-24 10:18:50.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>78124614</BTNumber>
    <CPNumber>78124614</CPNumber>
    <DialedNumber>7812461400</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>MyNetwork</CarrierCode>
    <DateStamp>2013-03-24 15:35:31.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>78124614</BTNumber>
    <CPNumber>78124614</CPNumber>
    <DialedNumber>7812461400</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>MyNetwork</CarrierCode>
    <DateStamp>2013-03-24 15:36:59.0</DateStamp>
</Row>
 </Results>

请建议其他任何内容比XMLSlurper更容易,更快捷。

2 个答案:

答案 0 :(得分:1)

首先,您的xml重复了<Results>。你需要吗?

您可以使用以下内容获取唯一id和相应count的地图:

def xmlObj = new XmlSlurper().parseText(xml)
def btNumbers = xmlObj.Row.collect{it.BTNumber} 
def countMap = btNumbers.unique(false).collectEntries{btNumber-> 
    [btNumber, btNumbers.count(btNumber)]
}

xml是你提到的xml元素。

<Results>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>2205867438</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>2461253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:50:04.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>2205867438</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>2461253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:50:18.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>2201159526</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>1111253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:53:07.0</DateStamp>
</Row>
<Row>
    <DialedCountry>001</DialedCountry>
    <BTNumber>1011159526</BTNumber>
    <CPNumber>0000000000</CPNumber>
    <DialedNumber>1111253052</DialedNumber>
    <Wireless>1</Wireless>
    <CarrierCode>customer1</CarrierCode>
    <DateStamp>2013-03-24 11:53:18.0</DateStamp>
</Row>
</Results>

答案 1 :(得分:0)

说有一个附加的数量字段,这是在此xml中检查类似BTnumbers值并在groovy中添加相应的QTY值的理想方法。