单击微调器(在弹出窗口中)时出现问题
这是我的弹出窗口:
public class PopupDialog extends PopupWindow {
public PopupDialog() {
super();
init();
}
public PopupDialog(View contentView, int width, int height) {
super(contentView, width, height);
init();
}
public PopupDialog(View contentView) {
super(contentView);
init();
}
private void init() {
this.setTouchable(true);
this.setFocusable(true);
this.setOutsideTouchable(true);
setBackgroundDrawable(new BitmapDrawable());
this.setTouchInterceptor(new OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {
PopupDialog.this.dismiss();
return true;
}
return false;
}
});
}
}
单击显示弹出窗口的按钮:
public void click(View v) {
LayoutInflater layoutInflater
= (LayoutInflater)getBaseContext()
.getSystemService(LAYOUT_INFLATER_SERVICE);
View popupView = layoutInflater.inflate(R.layout.popup, null);
final PopupDialog popupWindow = new PopupDialog(
popupView,
LayoutParams.WRAP_CONTENT,
LayoutParams.WRAP_CONTENT);
DisplayMetrics metrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(metrics);
popupWindow.setHeight(metrics.heightPixels);
popupWindow.setWidth(300);
popupWindow.showAtLocation(v, Gravity.NO_GRAVITY, v.getLeft()+v.getWidth(), 0);
}
我有这个异常(BadTokenException)
05-29 16:35:10.627: E/AndroidRuntime(1055): FATAL EXCEPTION: main
05-29 16:35:10.627: E/AndroidRuntime(1055): android.view.WindowManager$BadTokenException: Unable to add window -- token android.view.ViewRootImpl$W@410ad298 is not valid; is your activity running?
05-29 16:35:10.627: E/AndroidRuntime(1055): at android.view.ViewRootImpl.setView(ViewRootImpl.java:515)
05-29 16:35:10.627: E/AndroidRuntime(1055): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:279)
05-29 16:35:10.627: E/AndroidRuntime(1055): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:193)
05-29 16:35:10.627: E/AndroidRuntime(1055): at android.view.WindowManagerImpl$CompatModeWrapper.addView(WindowManagerImpl.java:118)
05-29 16:35:10.627: E/AndroidRuntime(1055): at android.view.Window$LocalWindowManager.addView(Window.java:537)
05-29 16:35:10.627: E/AndroidRuntime(1055): at android.widget.PopupWindow.invokePopup(PopupWindow.java:988)
05-29 16:35:10.627: E/AndroidRuntime(1055): at and
欢迎任何帮助,提前谢谢:)
答案 0 :(得分:9)
存在上下文冲突。尝试在XML微调器声明中添加它:android:spinnerMode="dialog"
答案 1 :(得分:0)
在这里做一个测试,
暂时删除这部分代码
this.setTouchInterceptor(new OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {
PopupDialog.this.dismiss();
return true;
}
return false;
}
});
并检查。
答案 2 :(得分:0)
我希望现在还为时不晚。 我遇到过同样的问题。
,事情进展顺利android:spinnerMode="dialog"
但是,我无法使用PopupWindow实现下拉列表(没有对话框弹出窗口)。 我通过使用 alertbuilder 来完成同样的工作。
您可以按照本教程操作: YT Link