Question

大家好我从很多1d列表创建2d列表时遇到了麻烦。我的代码如下：

  lis=[average, average1, average2, average3, average4, average5, average6, average7, average8, average9]
  totalaverage= 3


  print
  print "Station 1 = Station 0 from menu. Please read all other stations accordingly"
  print
  for i,x in enumerate(lis):
  if x < totalaverage:
    aboveaverage = " {} average is less than {}".format(i+1,totalaverage )


    option = 0
    comicdb = []

    record = {}
    record = aboveaverage
    comicdb.append(record)
    print comicdb


    elif x > totalaverage:
     belowaverage = "{} average is greater than {}".format(i+1,totalaverage)
     print belowaverage

当我打印comicdb时，我得到以下结果。

[' 1 average is less than 3']
[' 2 average is less than 3']
[' 3 average is less than 3']
[' 4 average is less than 3']
[' 5 average is less than 3']
[' 6 average is less than 3']
[' 7 average is less than 3']
[' 8 average is less than 3']
[' 9 average is less than 3']
[' 10 average is less than 3']

我想知道的是。是否有可以添加的代码，因此我可以将所有这些单个列表组合成一个双列表，以便我的代码在打印时看起来像这样。

[[' 1 average is less than 3'],
[' 2 average is less than 3'],
[' 3 average is less than 3'],
[' 4 average is less than 3'],
[' 5 average is less than 3'],
[' 6 average is less than 3'],
[' 7 average is less than 3'],
[' 8 average is less than 3'],
[' 9 average is less than 3'],
[' 10 average is less than 3']]

基本上我希望将所有这些单独的列表组合成一个双列表，以便我可以使用双列表分别访问每个列表。我想稍后在代码中单独打印每个列表。

Answer 1

在python中，您可以将列表附加到列表中。

new_list = []
for i,x in enumerate(lis):
if x < totalaverage:
    aboveaverage = " {} average is less than {}".format(i+1,totalaverage )
    option = 0
    comicdb = []
    record = {}
    record = aboveaverage
    comicdb.append(record)
    new_list.append(comicdb)
    print comicdb

    elif x > totalaverage:
        belowaverage = "{} average is greater than {}".format(i+1,totalaverage)
        print belowaverage
print new_list

从许多1d创建一个2d列表列出python

1 个答案: