我编写了一个' punishbox' (为惩罚玩家破坏规则)我的Crysis Wars服务器mod但由于某种原因我不断收到此错误:
[警告] [Lua错误] scripts / functions.lua:340:尝试对全局' t#进行算术运算。 (零值)
但问题是,tme
实际上是0到15之间的数字值。以下代码基本上设置了' punishbox'并检查它是否仍然对玩家有效。如您所见,tme
实际上是一个值(如果不是,则代码根本不会运行)。我在这里做错了吗?
由于这是一个特定的情况,我在互联网上找不到那么多。 tme
引用time
,它通过聊天命令转发给函数,绝对是一个数字。
另外,有没有更简单的方法呢?
代码:
function XPunishPlayer(Name, time, reason)
if (time > 5) then
System.LogAlways("[SYSTEM] Punished by administrator: "..Name:GetName().."");
end
if (not Msg) then
local tme = math.floor(time*60);
Msg = true;
XMessageChatToPlayer(Name, "[!punish] You were punished for "..time.." minutes: "..reason.."");
g_gameRules.game:RenamePlayer(Name.id, "[PUNISH]"..Name:GetName().."");
XMessageChatToPlayer(Name, "[!punish] You can use !pm to dispute this punishment.");
g_gameRules:KillPlayer(Name);
end
Script.SetTimer( 1000,function()
local tme = tme+1;
XPunishPlayer(Name, time, reason);
Name.actor:SetNanoSuitEnergy(0);
local punish = math.floor(timeleft-1);
g_gameRules.onClient:ClStepWorking(g_gameRules.game:GetChannelId(Name.id), tme);
if (tme == math.floor(time*60)) then
g_gameRules.onClient:ClStepWorking(g_gameRules.game:GetChannelId(Name.id), false);
XMessageChatToPlayer(Name, "[!punish] Released from the punishbox.");
XMessageInfoToAll("Unpunished "..Name:GetName()..", was punished for "..time.." minutes: "..reason.." (Server Administration)");
return;
end
end);
end
答案 0 :(得分:2)
您的tme
在if块中定义,在Lua中,每个块都会创建自己的闭包,因此tme
的值对于该块是本地的。
你可以通过简单地删除local
关键字(这通常不是一个好主意)使其成为全局变量,或者像这样在块之前定义它:
function XPunishPlayer(Name, time, reason)
if (time > 5) then
System.LogAlways("[SYSTEM] Punished by administrator: "..Name:GetName().."");
end
local tme;
if (not Msg) then
tme = math.floor(time*60);
[...]
end
Script.SetTimer( 1000,function()
tme = tme-1;
[...]
end);
end
我也很确定你local tme
内的第二个SetTimer
会给你带来另一个头痛......