Question

我在这里做错了什么？我一直在说：

#1064 - You have an error in your SQL syntax; check the manual that corresponds 
to your MySQL server version for the right syntax to use near 'INTO userID, 
currentStatus, failedLogin FROM access WHERE username = p_UserName ' at line 9

当然，这是我的惯例：

DELIMITER $$

DROP PROCEDURE IF EXISTS `user_login`$$

CREATE PROCEDURE `user_login`(IN v_UserName VARCHAR(45), IN v_Password VARCHAR(45), IN v_IP VARCHAR(45), IN v_Source VARCHAR(45))

BEGIN

    DECLARE userID INT(10);
    DECLARE currentStatus VARCHAR(10);
    DECLARE failedLogin INT(4);

    IF EXISTS(SELECT access_user_id, status, failed_login_count INTO userID, currentStatus, failedLogin FROM access WHERE username = v_UserName AND hash = v_Password LIMIT 1) THEN
        UPDATE access SET failed_login_count=0 WHERE access_user_id=userID;
        INSERT INTO last_login (profiles_user_id, timestamp, ip_address, login_source) VALUES (userID, NOW(), v_IP, v_Source) ON DUPLICATE KEY UPDATE timestamp=VALUES(timestamp), ip_address=VALUES(ip_address), login_source=VALUES(login_source);
        INSERT INTO login_history (profiles_user_id, timestamp, ip_address, login_source) VALUES (userID, NOW(), v_IP, v_Source);

        CASE currentStatus
            WHEN 'Active' THEN
                SELECT userID, currentStatus;
            WHEN 'Dormant' THEN
                UPDATE access SET status='Active' WHERE access_user_id=userID;
                SELECT userID, currentStatus;               
            WHEN 'Locked' THEN
                SELECT userID, currentStatus;
            ELSE

        END CASE;

    ELSE
        IF EXISTS(SELECT access_user_id, failed_login_count INTO userID, failedLogin FROM access WHERE username = p_UserName LIMIT 1) THEN
            failedLogin = failedLogin +1;
            UPDATE access SET failed_login_count=failedLogin WHERE access_user_id=userID;

            CASE failedLogin
                WHEN (<10) THEN
                    SELECT 0, 'Invalid';
                WHEN (>10) THEN
                    UPDATE access SET status='Locked' WHERE access_user_id=userID;
                    SELECT 0, 'Invalid';
                ELSE
                    UPDATE access Set failed_login_count=1 WHERE access_user_id=userID;
                    SELECT 0, 'Invalid';
            END CASE;

        ELSE
            SELECT 0, 'Invalid';
        END IF;
    END IF;
END$$

DELIMITER ;

我已经挖掘了MySQL 5.5文档并根据它，我的SELECT INTO语法是正确的......好吧，显然不是根据服务器...任何人都有任何想法？

Answer 1

存在一些问题：

在SELECT...INTO子句中使用EXISTS语句。你不能这样做因为SELECT ... INTO不返回结果集，它只是设置变量。解决方法（在IF语句中拆分查询并检查ID值）：

SELECT access_user_id, status, failed_login_count INTO userID, currentStatus, failedLogin FROM access WHERE username = p_UserName AND hash = p_Password LIMIT 1;

IF userID IS NOT NULL THEN
...

从第一个CASE结构中删除ELSE关键字。

上一个CASE结构有错误的语法，请尝试这个 -

CASE
  WHEN failedLogin < 10 THEN
    SELECT 0, 'Invalid';
  WHEN failedLogin > 10 THEN
    UPDATE access SET status='Locked' WHERE access_user_id=userID;
    SELECT 0, 'Invalid';
  ELSE
    UPDATE access Set failed_login_count=1 WHERE access_user_id=userID;
    SELECT 0, 'Invalid';
END CASE;

使用MySQL v 5.5的“选择INTO”例程会产生1064语法错误

1 个答案: