Question

我正在尝试将项目blueToothMe转换为我自己的用途。我已经更改了代码中的UUID

NSArray *characteristics = [NSArray arrayWithObjects:[CBUUID UUIDWithString:@"2A1E"], 
                                                         [CBUUID UUIDWithString:@"2A1C"],
                                                         [CBUUID UUIDWithString:@"2A21"], nil];

到

NSArray *characteristics = [NSArray arrayWithObjects:[CBUUID UUIDWithString:@"2A04"], 
                                                         [CBUUID UUIDWithString:@"2A03"],
                                                         [CBUUID UUIDWithString:@"2A19"], nil];

我可以从cc2540获得连接，但我无法获得任何特性服务。

我知道电池服务UUID并希望使用它们来让用户达到电池电量。

我试图替换：

[instance setCharacteristics:characteristics forServiceCBUUID:@"1809"];
[instance setLetWriteDataCBUUID:[NSArray arrayWithObject:@"1809"]];

characteristics = [NSArray arrayWithObject:[CBUUID UUIDWithString:@"2A29"]];

[instance setCharacteristics:characteristics forServiceCBUUID:@"180A"];

与

[instance setCharacteristics:characteristics forServiceCBUUID:@"2803"];
        [instance setLetWriteDataCBUUID:[NSArray arrayWithObject:@"2803"]];

        characteristics = [NSArray arrayWithObject:[CBUUID UUIDWithString:@"2A19"]];

        [instance setCharacteristics:characteristics forServiceCBUUID:@"180F"];

有没有人与此合作并有任何想法？

由于

适用于BluetoothMe的UUID

0 个答案: