Question

我试图通过Camel Route在Weblogic JMS的Queue上放置一条消息。

我的目标是最终配置一个Route来使用来自jms队列的消息，我从之前的Route发布数据。

这是我的配置：

<bean id="jndiTemplate" class="org.springframework.jndi.JndiTemplate">
    <property name="environment">
        <props>
            <prop key="java.naming.factory.initial">weblogic.jndi.WLInitialContextFactory</prop>
            <prop key="java.naming.provider.url">t3://localhost:7001</prop>
            <!-- opional ... -->
            <prop key="java.naming.security.principal">weblogic</prop>
            <prop key="java.naming.security.credentials">weblogic</prop>
        </props>
    </property>
</bean>

<!-- Gets a Weblogic JMS Connection factory object from JDNI Server by jndiName--> 
<bean id="webLogicJmsConnectionFactory" class="org.springframework.jndi.JndiObjectFactoryBean">
    <property name="jndiTemplate" ref="jndiTemplate" />
    <property name="jndiName" value="jms/TestConnectionFactory" />  <!-- the connection factory object is store under this name -->
</bean>

<!-- Create a new WebLogic Jms Camel Component -->
<bean id="wmq" class="org.apache.camel.component.jms.JmsComponent">
   <property name="connectionFactory" ref="webLogicJmsConnectionFactory"/>
</bean>

My Route看起来像这样：

from("cxfrs:bean:rsServer")
     .setBody().body(TestRequest.class)
     .process(new Processor(){
        @Override
        public void process(Exchange exchange) throws Exception {
            TestRequest request = exchange.getIn().getBody(TestRequest.class);
            TestResponse response = new TestResponse();
            response.setAddress(request.getAddress());
            response.setName(request.getName());
        }

     }).to("wmq:queue:TestJMSQueue");

当我尝试执行此路由时，我收到此异常：

May 27, 2013 6:37:47 PM org.apache.cxf.jaxrs.impl.WebApplicationExceptionMapper toResponse
WARNING: javax.ws.rs.WebApplicationException: org.springframework.jms.UncategorizedJmsException: Uncategorized exception occured during JMS processing; nested exception is weblogic.jms.common.JMSException: [JMSExceptions:045101]The destination name passed to createTopic or createQueue "TestJMSModule!TestJMSQueue" is invalid. If the destination name does not contain a "/" character then it must be the name of a distributed destination that is available in the cluster to which the client is attached. If it does contain a "/" character then the string before the "/" must be the name of a JMSServer or a ".". The string after the "/" is the name of a the desired destination. If the "./" version of the string is used then any destination with the given name on the local WLS server will be returned.
at org.apache.camel.component.cxf.jaxrs.CxfRsInvoker.returnResponse(CxfRsInvoker.java:149)
at org.apache.camel.component.cxf.jaxrs.CxfRsInvoker.asyncInvoke(CxfRsInvoker.java:104)
at org.apache.camel.component.cxf.jaxrs.CxfRsInvoker.performInvocation(CxfRsInvoker.java:57)
at org.apache.cxf.service.invoker.AbstractInvoker.invoke(AbstractInvoker.java:96)
at org.apache.cxf.jaxrs.JAXRSInvoker.invoke(JAXRSInvoker.java:167)
at org.apache.cxf.jaxrs.JAXRSInvoker.invoke(JAXRSInvoker.java:94)
at org.apache.cxf.interceptor.ServiceInvokerInterceptor$1.run(ServiceInvokerInterceptor.java:58)
at org.apache.cxf.interceptor.ServiceInvokerInterceptor.handleMessage(ServiceInvokerInterceptor
...
Caused by: weblogic.jms.common.JMSException: [JMSExceptions:045101]The destination name passed to createTopic or createQueue "TestJMSModule!TestJMSQueue" is invalid. If the destination name does not contain a "/" character then it must be the name of a distributed destination that is available in the cluster to which the client is attached. If it does contain a "/" character then the string before the "/" must be the name of a JMSServer or a ".". The string after the "/" is the name of a the desired destination. If the "./" version of the string is used then any destination with the given name on the local WLS server will be returned.
at weblogic.jms.frontend.FEManager.destinationCreate(FEManager.java:202)
at weblogic.jms.frontend.FEManager.invoke(FEManager.java:544)
at weblogic.messaging.dispatcher.Request.wrappedFiniteStateMachine(Request.java:961)
at weblogic.messaging.dispatcher.DispatcherImpl.syncRequest(DispatcherImpl.java:184)
at weblogic.messaging.dispatcher.DispatcherImpl.dispatchSyncNoTran(DispatcherImpl.java:287)
at weblogic.jms.dispatcher.DispatcherAdapter.dispatchSyncNoTran(DispatcherAdapter.java:59)
at weblogic.jms.client.JMSSession.createDestination(JMSSession.java:3118)
at weblogic.jms.client.JMSSession.createQueue(JMSSession.java:2514)

我按照程序创建了这里提到的队列：https://blogs.oracle.com/soaproactive/entry/how_to_create_a_simple

我正在创建一个JMS模块（TestJMSModule），我正在创建一个Queue（TestJMSQueue）和一个连接工厂。

我是JMS的新手，我知道我在Camel方面或Weblogic方面的配置有问题，但无法弄清楚是什么。任何帮助将不胜感激。

提前致谢。

Answer 1

您需要创建JMS服务器。然后，您需要在JMS模块中创建子部署，然后将子部署目标指向JMS服务器。

然后语法需要 JMSServer / JMSModule！队列

Answer 2

不幸的是，我不是WebLogic配置方面的专家。客户端配置看起来正确。例外情况说对象名称不正确。在示例中，您提到队列的jndi名称是“jms / TestJMSQueue”，而不仅仅是“TestJMSQueue”。对我而言，这意味着您应该使用.to("wmq:queue:jms/TestJMSQueue");代替。

Answer 3

我要集成Spring（4.1.6）+ Apache Camel（2.15.2）并使用Oracle Weblogic（11g）上托管的JMS队列中的消息。

applicationContext.xml中

<bean id="jndiTemplate" class="org.springframework.jndi.JndiTemplate">
    <property name="environment">
        <props>
            <prop key="java.naming.factory.initial">weblogic.jndi.WLInitialContextFactory</prop>
            <prop key="java.naming.provider.url">t3://localhost:7001</prop>
            <prop key="java.naming.security.principal">weblogic</prop>
            <prop key="java.naming.security.credentials">welcome1</prop>
        </props>
    </property>
</bean>

<bean id="webLogicJmsConnectionFactory" class="org.springframework.jndi.JndiObjectFactoryBean">
    <property name="jndiTemplate" ref="jndiTemplate" />
    <!-- Connection factory JNDI name -->
    <property name="jndiName" value="jms/TestConnectionFactory" />
</bean>

<bean id="weblogicJmsComponent" class="org.apache.camel.component.jms.JmsComponent">
    <property name="connectionFactory" ref="webLogicJmsConnectionFactory" />
</bean>

<camel:camelContext id="camel" xmlns:camel="http://camel.apache.org/schema/spring">
    <!-- Route to copy files -->
    <camel:route startupOrder="1">
        <camel:from uri="file:data/inbox?noop=true" />
        <camel:process ref="loggingProcessor" />
        <camel:to uri="file:data/outbox" />
    </camel:route>

    <!-- Route to read from JMS and process them in jmsReaderProcessor -->
    <camel:route startupOrder="2">
        <camel:from uri="weblogicJmsComponent:queue:TestJMSServer/TestJMSModule!TestJMSQueue" />
        <camel:process ref="jmsReaderProcessor" />
    </camel:route>
</camel:camelContext>

loggingProcessor和jmsReaderProcessor是两个Camel处理器，它只是从Exchange对象输入/输出消息。

public void process(Exchange exchange) throws Exception {
    LOG.info("begin process()");
    LOG.info("process() -- Got exchange: {}", exchange);

    Message messageIn = exchange.getIn();
    LOG.info("process() -- Got messageIn: {}", messageIn);

    LOG.info("process() -- Got messageIn.getBody(): {}", messageIn.getBody());

    Message messageOut = exchange.getOut();
    LOG.info("process() -- Got messageOut: {}", messageOut);

    LOG.info("end process()");
}

亲切的问候，

Cristian Manoliu

从Camel Route向Weblogic JMS Queue发送消息

3 个答案: