在linq-to-sql查询中将字符串转换为int:如何处理无法转换的值?

时间:2013-05-27 12:32:54

标签: c# .net linq-to-sql

我正在针对数据库运行此查询:

var result = (from leads in dc.T_DM_FactDemandeWebLeads
                         join  demands in dc.T_DM_DimDemandeWebs on leads.DemandeWeb_FK equals demands.DemandeWeb_PK
                         join  temps in dc.T_DM_Temps on demands.DateDemande_FK equals temps.Temps_PK
                         where leads.longitudeClient != null && (Convert.ToInt32(leads.GeolocDistanceRouteDistrib) > 1000*30) && (temps.Date > new DateTime(2000, 1, 1).Date)
                         select new Lead
                         {

                             lng = leads.longitudeClient,     

                             lat = leads.latitudeClient,

                             distance = leads.GeolocDistanceRouteDistrib

                         }).Take(1000000);

问题:此行有问题:

(Convert.ToInt32(leads.GeolocDistanceRouteDistrib) > 1000*30)

as leads.GeolocDistanceRouteDistrib是一个VARCHAR,在某些情况下采用“未知”,导致format exception

Conversion failed when converting the varchar value 'Unknown' to data type int.

此问题已解决here,但该方法无法转换为SQL。

问题:有没有办法重写查询,以便在执行查询期间完成转换?

2 个答案:

答案 0 :(得分:2)

使用this answer中的技术在dbml文件中创建IsNumeric sql函数。 并在查询中使用它。

这样的事情:

join  temps in dc.T_DM_Temps on demands.DateDemande_FK equals temps.Temps_PK
where dc.ISNUMERIC(leads.GeolocDistanceRouteDistrib) // Added!
where leads.longitudeClient != null && (Convert.ToInt32(leads.GeolocDistanceRouteDistrib) > 1000*30) && (temps.Date > new DateTime(2000, 1, 1).Date)
select new Lead

答案 1 :(得分:1)

.AsEnumerable()添加到您的实体,然后您可以使用所有方法

var result = (from leads in dc.T_DM_FactDemandeWebLeads.AsEnumerable()
                         join  demands in dc.T_DM_DimDemandeWebs on leads.DemandeWeb_FK equals demands.DemandeWeb_PK
                         join  temps in dc.T_DM_Temps on demands.DateDemande_FK equals temps.Temps_PK
                         where leads.longitudeClient != null && (Convert.ToInt32(leads.GeolocDistanceRouteDistrib) > 1000*30) && (temps.Date > new DateTime(2000, 1, 1).Date)
                         select new Lead
                         {
                             lng = leads.longitudeClient,     
                             lat = leads.latitudeClient,
                             distance = leads.GeolocDistanceRouteDistrib
                         }).Take(1000000);