Question

请帮我解析这个xml标签，我想用类别ID解析这个xml标签如下......？

期望的输出：

apple     100    iphone 5    500$ 
apple     200    iphone 4s   300$ 
Samsung   300    Galaxy 4    400$

XML示例在这里：

<Items>
   <category ID="99">
      <MobileDetails>
         <MobileName>apple</MobileName>
         <MobileID>100</MobileID>
         <MobileModel>iphone 5</MobileModel>
         <MobileCost>500$</MobileCost>
      </MobileDetails>
      <MobileDetails>
        <MobileName>apple</MobileName>
        <MobileID>200</MobileID>
        <MobileModel>iphone 4s</MobileModel>
        <MobileCost>300$</MobileCost>
      </MobileDetails>
   </category >
   <category ID="100">
     <MobileDetails>
       <MobileName>Samsung</MobileName>
       <MobileID>300</MobileID>
       <MobileModel>Galaxy 4</MobileModel>
       <MobileCost>400$</MobileCost>
     </MobileDetails>   
  </category >
</Items>

Answer 1

   try {
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document doc = builder.parse(new InputSource(new StringReader(xml)));
        Element root =(Element) doc.getDocumentElement();
        //category
        NodeList categoryNList = root.getElementsByTagName("category");
        int categoryLength = categoryNList.getLength();
        for (int i = 0; i < categoryLength; i++) {
           Element element = (Element)categoryNList.item(i);
           //fetch ID
           String categoryID = element.getAttribute("ID");
           NodeList mobileDetailsNList = element.getElementsByTagName("MobileDetails");
           //inner
           int MobileDetailsLength = elemnt.getElementsByTagName("MobileName");
           for(int j==0;int < j <MobileDetailsLength  ; j++) {
           NodeList MobileDetailsNList = element.getElementsByTagName("MobileDetails");
           Element element = (Element)categoryNList.item(i);
           String name = mobileDetailsNList.item(0).getFirstChild().getNodeValue() ;
           //... ... ...
           //... ... ...

           }

       }

  } catch (Exception e) {

  }
}
maybe it will help you.

Android XML Parser使用属性

1 个答案: