Question

我正在制作一个基于文本的游戏并且一直很好但现在但我遇到了int的错误。到目前为止我的代码看起来像这样：

money = 500
print("You Have $500 To Spend On Your City.  The Population Is 0 People")
input_var3 = input("What Will You Spend Your Money On?  A House Or A Restraunt. ")
if input_var3 == "House":
    money - 100
    print("You Have Spent Your Money On A House")
    print("You Now Have $" + money)
if input_var3 == "Restraunt":
    money - 150
    print("You Have Spent Your Money On A Restraunt")
    print("You Now Have $" + money)

你的钱等于500美元，但是如果你把它花在一个房子或限制上，你将会有更少的钱，而且外壳会打印你剩下多少钱。但是我总是得到这个错误：

Traceback (most recent call last):
  File "C:\Users\Jason\Desktop\City Text.py", line 11, in <module>
    print("You Now Have $" + money)
TypeError: Can't convert 'int' object to str implicitly

我已经意识到我必须做一个sting而不是Int，但我不知道该怎么做。有人可以帮忙吗？

Answer 1

money变量是整数。将它们连接在一起时，不能将整数与字符串混合在一起。使用str()函数将整数转换为字符串：

print("You Now Have $" + str(money))

另外，我认为你打算从货币价值中拿走100。 money - 100只返回500 - 100，即400。如果您想让money等于400，请执行：

money -= 100

相当于：

money = money - 100

Answer 2

您需要将值存储在变量中。

if input_var3 == "House":
    money -= 100   # Notice the usage of -=
    print("You Have Spent Your Money On A House")
    print("You Now Have $" + str(money))   # Type casting
if input_var3 == "Restraunt":
    money = money - 150  # Same as -=
    print("You Have Spent Your Money On A Restraunt")
    print("You Now Have $" + str(money))   # Type casting

Answer 3

使用：

print("You Now Have $" + str(money))

您无法将字符串与数字连接，因此请将您的数字转换为字符串。

Answer 4

您可以使用str()功能。例如：

print("You Now Have $" + str(money))

从Int和印刷中减去

4 个答案: