您好我正在尝试将一个名为url的变量从javascript传递到同一页面中名为parse的php函数，这是我的以下尝试，但它没有呈现任何内容。我也试图在函数解析中使用它。我做错了什么？注意：为了简单起见，函数解析完全被删除了。它实际上做的不仅仅是回显一个变量，它还有更多的html。
这是我在php脚本里面的javascript脚本中的AJAX REQUEST。
"<script type=\"text/javascript\">\n".
"\n".
"// create and return an XMLHttpRequest object\n".
"function createRequest() {\n".
" var ajaxRequest; // the xmlrequest object\n".
" try{\n".
" // Opera 8.0+, Firefox, Safari\n".
" ajaxRequest = new XMLHttpRequest();\n".
" } catch (e){\n".
" // Internet Explorer Browsers\n".
" try{\n".
" ajaxRequest = new ActiveXObject(\"Msxml2.XMLHTTP\");\n".
" } catch (e) {\n".
" try{\n".
" ajaxRequest = new ActiveXObject(\"Microsoft.XMLHTTP\");\n".
" } catch (e){\n".
" // Something went wrong\n".
" alert(\"Your browser broke!\");\n".
" return false;\n".
" }\n".
" }\n".
" }\n".
" return ajaxRequest;\n".
"} // end of createRequest\n".
这是我的实际javascript，以及我要传递的变量url和函数解析的innerhtml
"var spellcheck = function(data){\n".
" var found=false;var url='';\n".
" var text=data[0];\n".
" if(text!=document.getElementById('spellcheckinput').value)return;\n".
" for(i=0;i<data[1].length;i++){if(text.toLowerCase()==data[1][i].toLowerCase()){found=true;url='http://en.wikipedia.org/wiki/'+text;document.getElementById('spellcheckresult').innerHTML='<b style=\"color:green\">Correct</b> - <a target=\"_top\" href=\"'+url+'\">link</a>';}}\n".
" if(!found)\n".
" document.getElementById('spellcheckresult').innerHTML='<b style=\"color:red\">Incorrect</b>';};\n".
" var getjs= function(value){\n".
" if(!value)return;".
" var url='http://en.wikipedia.org/w/api.php?action=opensearch&search='+value+'&format=json&callback=spellcheck';". // this is the variable I want to pass
"document.getElementById('spellcheckresult').innerHTML='Checking ...';".
"var elem=document.createElement('script');".
"elem.setAttribute('src',url);".
"elem.setAttribute('type','text/javascript');".
"document.getElementsByTagName('head')[0].appendChild(elem);};\n".
"document.getElementById('resultdiv').innerHTML='" . parse() . "';\n". //here wanting to innerhtml my php function
这是我的不成功的ajax JavaScript变量传递到我的php函数下面
" var requestone = createRequest();"
"var variabletosend = url;"
"var vars = "deletenode=" + encodeURIComponent(variabletosend);"
"requestone.open("POST", "parse()", true);"
"requestone.setRequestHeader("Content-type", "application/x-www-form-urlencoded");"
"requestone.onreadystatechange = function(){"
"handleRequest(requestone);"
"}"
"requestone.send(vars);"
"</script>\n".
"\n".
"<form action=\"#\" method=\"get\" onsubmit=\"return false\">\n".
"<p>Enter a species here : <input id=\"spellcheckinput\" onkeyup=\"getjs (this.value);\" type=\"text\"> <span id=\"spellcheckresult\"></span></p>\n".
"</form>\n".
"<div id=resultdiv></div>".
"</body>\n".
"</html>\n".
"\n";
function parse($url){
print $url;
}
?>
答案 0 :(得分：0)
嗯，你的ajax电话是错误的。你不能用AJAX调用php函数。你可以调用一个php页面，whitch有一个php函数。因此，您需要使用您的参数调用您的页面。 如果你检测到param，那么执行parse（），如果没有，则回显javascript代码。
假设您的代码位于名为“parser.php”的页面中，以下是一个应该有效的代码：
<?php
//We check if we have the param within the page call
$theDeletenode = false;
if(isset($_POST['deletenode']))
$theDeletenode = $_POST['deletenode'];
if($theDeletenode)
{
//The param 'deletenode' is given, so we juste have to call the php function "parse", to return the value
parse($theDeletenode);
}else
{
// No parametre, so we echo the javascript, and the form (without the quote and \n, it's much better)
?>
<html><head>
<script type="text/javascript">
// create and return an XMLHttpRequest object
function createRequest() {
var ajaxRequest; // the xmlrequest object
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
return ajaxRequest;
}; // end of createRequest
var spellcheck = function(data){
var found=false;var url='';
var text=data[0];
if(text!=document.getElementById('spellcheckinput').value) return;
for(i=0;i<data[1].length;i++)
{
if(text.toLowerCase()==data[1][i].toLowerCase())
{found=true;
url='http://en.wikipedia.org/wiki/'+text;document.getElementById('spellcheckresult').innerHTML='<b style=\"color:green\">Correct</b> - <a target=\"_top\" href=\"'+url+'\">link</a>';
}
}
if(!found)
document.getElementById('spellcheckresult').innerHTML='<b style=\"color:red\">Incorrect</b>';
};
var requestone = createRequest();
var getjs= function(value)
{
if(!value) return;
var url='http://en.wikipedia.org/w/api.php?action=opensearch&search='+value+'&format=json&callback=spellcheck'; // this is the variable I want to pass
document.getElementById('spellcheckresult').innerHTML='Checking ...';
var elem=document.createElement('script');
elem.setAttribute('src',url);
elem.setAttribute('type','text/javascript');
document.getElementsByTagName('head')[0].appendChild(elem);
// Ajax call to this page, this time with the 'deletenode' parameter
var vars = "deletenode=" + encodeURIComponent(url);
requestone.open("POST", "parser.php", true); // parser.php : the name of this current page
requestone.onreadystatechange = handleRequest; // function to handle the response
requestone.setRequestHeader('Content-Type','application/x-www-form-urlencoded');
requestone.send(vars);
};
function handleRequest()
{
//here we handle the php page response by echoing de result of the php page (normally the result of the parse function)
try{
if(requestone.readyState == 4 && requestone.status == 200)
document.getElementById('resultdiv').innerHTML= requestone.responseText;
} catch (e) {
//Wrong server answer...
}
};
</script>
</head>
<body>
<form action="#" method="get" onsubmit="return false">
<p>Enter a species here : <input id="spellcheckinput" onkeyup="getjs (this.value);" type="text"> <span id="spellcheckresult"></span></p>
</form>
<div id=resultdiv></div>
</body>
</html>
<?php
// end of the javascript+form echo
}
function parse($url){
// this function is only called when the POST param is given
print $url;
}
?>