如何将多个表链接到单个ID

时间:2013-05-25 17:06:01

标签: php mysql database database-design normalization

我正在尝试创建一个数据库(使用PHP和MYSQL,使用XAMPP),它存储有关各种快餐店及其分支机构的信息,以及在其分支机构提供的菜单。我在我的数据库中创建了一些表详细介绍快餐店及其分店,菜单的类别和子类别及其在表格中提供的项目的信息。表格的提示/样本如下所示。

Restaurants
+-------------+----------------+
| RestaurantID| RestaurantName | 
+-------------+----------------+
|     1       | PizzaHut       |
|     2       | BurgerKing     |
|     3       | KFC            | 
|     4       | SubWay         |
+-------------+----------------+

Branches
+---------------+----------------+
| RestaurantName| BranchAddress  | 
+---------------+----------------+
|   KFC         | XXX-1234       |
|   KFC         | AAA-1234       |
|   KFC         | YYY-1234       | 
|   BurgerKing  | DDD-1234       |
+---------------+----------------+

Categories
+---------------+----------------+
| BranchAddress | Categories     | 
+---------------+----------------+
|   XXX-1234    | Fries          |
|   AAA-1234    | Burgers        |
|   YYY-1234    | Drinks         | 
|   DDD-1234    | Burgers        |
+---------------+----------------+

SubCategories
+---------------+----------------+
| Categories    | SubCategories  | 
+---------------+----------------+
|   Fries       | Cheese         |
|   Burgers     | Chicken        |
|   Drinks      | Carbonated     | 
|   Burgers     | Beef           |
+---------------+----------------+

Items
+---------------+----------------+
| SubCategories | Items          | 
+---------------+----------------+
|   Cheese      | CheeseFries    |
|   Chicken     | Zinger         |
|   Carbonated  | Pepsi          | 
|   Beef        | Whopper        |
+---------------+----------------+

从上面可以看出,每个餐厅可以有几个分支,每个分支可以有几个类别,每个类别可以有几个子类别,然后可以有几个项目。分支可以有相同的类别和/或子类别但它们内部有不同的项目。

我不认为集中的类别,子类别和项目表在这种情况下会起作用,因为每个餐馆的每个分支都是它自己独立的个体实体,这需要它自己的一组类别,子类别和项目如果是这样,我如何创建表格,以及设置必要的外键?

Categories
+----------------+
|  Categories    |
+----------------+
|  Drinks        |
|  Burgers       | 
|  Fries         | 
|  SetMeals      |  
+----------------+

SubCategories
+----------------+----------------+
| Category       |  SubCategories |
+---------------+-----------------+
| Drinks         | Carbonated     |
| Drinks         | Carbonated     |
| Drinks         | Carbonated     |
| Drinks         | Non-Carbonated |
| Burgers        | Beef           |
| Burgers        | Beef           |
| Burgers        | Chicken        |
+----------------+----------------+

SubCategories
+----------------+----------------+-------------+
| Category       |  SubCategories | Items       |
+---------------+-----------------+-------------+
| Drinks         | Carbonated     | Pepsi        |
| Drinks         | Carbonated     | Root Beer    |
| Drinks         | Carbonated     | Cola         |
| Drinks         | Non-Carbonated | Orange Juice |
| Burgers        | Beef           | Whopper      |
| Burgers        | Beef           | Cheese Burger|
| Burgers        | Chicken        | McChicken    |
+----------------+----------------+--------------+

当然,我可能是错的,并且可以在这种情况下使用集中表。如果是这样,我可以提供一些关于如何进行/或设置表格的示例和/或说明吗?

我想到了以下解决方案:

Restaurants
+-------------+----------------+
| RestaurantID| RestaurantName | 
+-------------+----------------+
|     1       | PizzaHut       |
|     2       | BurgerKing     |
|     3       | KFC            | 
|     4       | SubWay         |
+-------------+----------------+

Branches
+---------------+----------------+
| RestaurantName| BranchAddress  | 
+---------------+----------------+
|  KFC          | XXX-1234       |
|  KFC          | AAA-1234       |
|  KFC          | YYY-1234       | 
|  BurgerKing   | DDD-1234       |
+-------------+------------------+

Categories
+----------------+----------------+----------------+
| RestaurantName | BranchAddress  | Category       | 
+----------------+-----------------+----------------+
|  KFC           |     XXX-1234   | Fries          |
|  KFC           |     AAA-1234   | Burgers        |
|  KFC           |     YYY-1234   | Drinks         | 
|  BurgerKing    |     DDD-1234   | Burgers        |
+----------------+----------------------------------+

SubCategories
+----------------+----------------+----------------+----------------+
| RestaurantName | BranchAddress  | Category       |  SubCategories |
+----------------+-----------------+---------------+----------------+
|  KFC           |     XXX-1234   | Fries          | Cheese         |
|  KFC           |     AAA-1234   | Burgers        | Chicken        |
|  KFC           |     YYY-1234   | Drinks         | Carbonated     |
|  BurgerKing    |     DDD-1234   | Burgers        | Beef           |
+----------------+---------------------------------+----------------+

Items
+----------------+----------------+----------------+----------------+-------------+
| RestaurantName | BranchAddress  | Category       |  SubCategories | Items       |
+----------------+-----------------+---------------+----------------+-------------+
|  KFC           |     XXX-1234   | Fries          | Cheese         |CheeseFries  |
|  KFC           |     AAA-1234   | Burgers        | Chicken        |Zinger       |
|  KFC           |     YYY-1234   | Drinks         | Carbonated     |Pepsi        |
|  BurgerKing    |     DDD-1234   | Burgers        | Beef           |Whopper      |
+----------------+---------------------------------+----------------+-------------+

虽然上面的表格给每个餐厅及其分支机构提供了各自的类别,子类别,项目,但它首先打破了将它们分开的整个目的,而且非常愚蠢。

编辑:我试图对上面的表进行非规范化,以便我可以使用

进行查询
$query="SELECT * FROM Items WHERE Restaurantname='BurgerKing' AND 
BranchAddress='XXX-1234' AND Category='Fries';
$result=mysqli_query($cxn,$query) or die("Error");
while($row=mysqli_fetch_assoc)
{
extract($row);
echo "$Item";
}

注意:我计划将数据库扩展到未来包括非快餐店甚至非F& B相关商店,因此各种表格(类别/子类别和项目)将会必须能够包括非F& B相关商店的类别(例如电子产品/书籍等)

我为非常长的问题道歉,并希望得到任何建议和帮助。

谢谢!

1 个答案:

答案 0 :(得分:0)

不确定为什么你要正常化。您可以从分类和子类别中取出与分支相关的列,从子类别中取出类别名称等。通过将它们留在您中,您可以复制大量数据,而不是传统上使用关系数据库的方式!您还应该按ID而不是通过名称关联这些表,因为加入时的比较更快。

您可以考虑使用多对多链接表将项链接到分支。这样,您就可以满足您的要求,即能够将类别/子类别的特定项目与分支相关联,而无需关联整个类别/子类别。

CREATE TABLE item_link (
  id INT(11) NOT NULL AUTO_INCREMENT PRIMARY KEY,
  branch_id INT(11) NOT NULL,
  item_id INT(11) NOT NULL,
  KEY composite (`branch_id`, `item_id`)
);

请参阅我为您制作的fiddle详细说明了我对架构的建议更改,并举例说明了如何使用此新表来显示分支的菜单/库存。