Question

我想回显数组中的多行，但它只输出一行： PHP

$query = "SELECT * FROM user WHERE Category = 'Men'";
$result = mysql_query($query);
   while ($row1 = mysql_fetch_array($result)) {
     $fname1 = $row1['FName'];       
     $sname1 = $row1['SName'];
     }

$result2 = mysql_query($query);
   while ($row2 = mysql_fetch_array($result2)) {
     $fname2 = $row2['FName'];       
     $sname2 = $row2['SName'];
     }

HTML

<h2>First Name: <?php echo "$fname1"; ?></h2>
<h2>Second Name: <?php echo "$sname1"; ?></h2>

<h2>First Name: <?php echo "$fname2"; ?></h2>
<h2>Second Name: <?php echo "$sname2"; ?></h2>

但是当两者都不同时，它给出了相同的输出。输出是：

名字：约翰第二名：史密斯

当我希望输出为：

名字：约翰第二名：史密斯

名字：鲍勃第二名：马利

有人可以帮我解决这个问题吗？\

数据库中的数据是：

User_ID| FName |SName| Category
1        John   Smith  Men
2        Bob    Marley Men

Answer 1

while循环会一遍又一遍地覆盖你的变量而只输出最后的结果，你必须将echo放在while中或者将它保存到数组然后循环遍历数组

也必须“停止使用mysql_ functions”并更改为PDO：）

您的代码的解决方案将是

$query = "SELECT * FROM user WHERE Category = 'Men'";
$result = mysql_query($query);
while ($row1 = mysql_fetch_array($result)) {
?> <h2>First Name: <?php echo $row1['FName']; ?></h2>
  <h2>Second Name: <?php echo $row1['SName']; ?></h2><?php       
}

Answer 2

使用数组，也只是跟踪你的代码。

PHP：

$query = "SELECT * FROM user WHERE Category = 'Men'";
$result = mysql_query($query);
   $fname=array();
   $sname=array();

   for($i=0;$i<2 && ($row = mysql_fetch_array($result));$i++) {
     $fname[$i] = $row['FName'];       
     $sname[$i] = $row['SName'];
     }

HTML：

<h2>First Name: <?php echo "$fname[0]"; ?></h2>
<h2>Second Name: <?php echo "$sname[0]"; ?></h2>

<h2>First Name: <?php echo "$fname[1]"; ?></h2>
<h2>Second Name: <?php echo "$sname[1]"; ?></h2>

Answer 3

$query = "SELECT * FROM user WHERE Category = 'Men'";
$result = mysql_query($query);
while ($row1 = mysql_fetch_array($result)) {
 $fname1 = $row1['FName'];       
 $sname1 = $row1['SName'];
echo " <h2>First Name: $fname1</h2>";
echo "<h2>Second Name: $sname1</h2>";
 }

Answer 4

您正在覆盖您的值，因为您的while循环每次都在迭代每一行。试试这个：

$query = "SELECT * FROM user WHERE Category = 'Men'";
// mysql_ = bad. mysqli_ = good!
$result = mysql_query($query);
$row1 = mysql_fetch_array($result);
$fname1 = $row1['FName'];
$sname1 = $row1['SName'];

// using the same $result.
$row2 = mysql_fetch_array($result);
$fname2 = $row2['FName'];       
$sname2 = $row2['SName'];

当然，正如其他地方所述，如果您的表中有两个以上的项目并且想要输出中的每个项目，那么此解决方案将无效。如果是这种情况，你会想要这样的东西：

$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{
?>  <h2>First Name: <?=$row['FName'] ?></h2>
    <h2>Second Name: <?=$row['SName'] ?></h2><br /><?php
}

或者，根据您的需要：

$result = mysql_query($query);
$men = array();
while($row = mysql_fetch_array($result))
{
    $men[] = $row;
}

// then later in the script
foreach($men as $man)
{
    // extract takes all of the array keys and turns them into local variables.
    // just make sure you read the warnings in the docs:
    // http://php.net/manual/en/function.extract.php
    extract($man);
    ?>  
    <h2>First Name: <?=$FName ?></h2>
    <h2>Second Name: <?=$SName ?></h2><br /><?php
}

PHP打印数组中的行

4 个答案: