Question

我将消息从弹出窗口发送到后台进程。反馈信号对我来说不是必需的。我可以不拨打sendResponse。

popup.js

window.onload = function(){
    chrome.extension.sendMessage('Hi, i opened');
}

background.js

chrome.runtime.onMessage.addListener(function(request, sender, sendResponse){
    console.log(request);
    console.log(sendResponse);
    // sendResponse not called
})

在sendmessage responseCallback可选函数developer.chrome.com/extensions/runtime.html#method-sendMessage

的文档中

如果我不转移responseCallback，请发送sendResponse。上面的代码打印出来。

function (response) {
    if (port) {
        port.postMessage(response);
        port.destroy_();
        port = null;
      } else {
        // We nulled out port when sending the response, and now the page
        // is trying to send another response for the same request.
        handleSendRequestError(isSendMessage, responseCallbackPreserved,
                               sourceExtensionId, targetExtensionId);
      }
    }

删除端口的功能。如果不调用sendResponse

，肯定会出现内存泄漏

Answer 1

根据我的理解，您希望向background.js发送消息，并且不希望收到回复。如果我是正确的，那么您只需要发送消息并忘记“sendResponse”。让我告诉你。

内容，JS

window.onload = function(){ chrome.extension.sendMessage('Hi, i opened'); }

在 background.js
中
chrome.runtime.onMessage.addListener(function(request, sender, sendResponse){ console.log(request); //console.log(sendResponse); // **this line is not needed** // just do what ever you want to do with the "request", it has the message // content.js sent. });

不使用responseCallback调用sendMessage

1 个答案: