我编写了一个简单的C#函数,通过以下API调用从MtGox检索交易历史记录:
https://data.mtgox.com/api/1/BTCUSD/trades?since=<trade_id>
在此处记录:https://en.bitcoin.it/wiki/MtGox/API/HTTP/v1#Multi_currency_trades
这是功能:
string GetTradesOnline(Int64 tid)
{
Thread.Sleep(30000);
// communicate
string url = "https://data.mtgox.com/api/1/BTCUSD/trades?since=" + tid.ToString();
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
StreamReader reader = new StreamReader(response.GetResponseStream());
string json = reader.ReadToEnd();
reader.Close();
reader.Dispose();
response.Close();
return json;
}
我从tid = 0(交易ID)开始获取数据(从一开始)。对于每个请求,我收到一个包含1000个交易详情的回复。我总是从前一个响应中发送交易ID以用于下一个请求。它适用于4个请求&amp;响应。但在此之后,以下行抛出“System.Net.WebException”,表示“操作已超时”:
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
这是事实:
任何可能出错的想法?
答案 0 :(得分:22)
我遇到了同样的问题。 对我来说,修复就像使用块包装HttpWebResponse代码一样简单。
using (HttpWebResponse response = (HttpWebResponse) request.GetResponse())
{
// Do your processings here....
}
详细信息:当向同一主机发出多个请求并且WebResponse
未正确处理时,通常会发生此问题。这就是using
块正确处理WebResponse
对象并从而解决问题的地方。
答案 1 :(得分:18)
有两种超时。客户端超时和服务器超时。你有没有试过这样的事情:
request.Timeout = Timeout.Infinite;
request.KeepAlive = true;
尝试这样的事情......
答案 2 :(得分:8)
我遇到类似的问题,通过ssl在LINUX服务器上调用REST服务。在尝试了许多不同的配置方案后,我发现我必须在http头中发送一个UserAgent。
这是我调用REST API的最终方法。
private static string RunWebRequest(string url, string json)
{
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
// Header
request.ContentType = "application/json";
request.Method = "POST";
request.AllowAutoRedirect = false;
request.KeepAlive = false;
request.Timeout = 30000;
request.ReadWriteTimeout = 30000;
request.UserAgent = "test.net";
request.Accept = "application/json";
request.ProtocolVersion = HttpVersion.Version11;
request.Headers.Add("Accept-Language","de_DE");
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls;
ServicePointManager.ServerCertificateValidationCallback = delegate { return true; };
byte[] bytes = Encoding.UTF8.GetBytes(json);
request.ContentLength = bytes.Length;
using (var writer = request.GetRequestStream())
{
writer.Write(bytes, 0, bytes.Length);
writer.Flush();
writer.Close();
}
var httpResponse = (HttpWebResponse)request.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
var jsonReturn = streamReader.ReadToEnd();
return jsonReturn;
}
}
答案 3 :(得分:1)
为了它的价值,我每次使用它时都会遇到与超时相同的问题,即使呼叫已经通过我正在呼叫的服务器。我的问题是我将Expect设置为application / json,而不是服务器返回的内容。
答案 4 :(得分:0)
这不是解决方案,而是替代方案: 这些天我几乎只使用WebClient而不是HttpWebRequest。尤其是用于POST和PUT的WebClient.UploadString和WebClient.DownloadString。这些只是获取并返回字符串。这样,除了获得WebException时,我不必处理流对象。如果需要,我还可以使用WebClient.Headers [“ Content-type”]设置内容类型。 using语句还可以通过为我致电Dispose使生活更轻松。
出于性能方面的考虑,我将System.Net.ServicePointManager.DefaultConnectionLimit设置为较高,而使用HttpClient及其Async方法进行同时调用。
这就是我现在要这样做的方式
string GetTradesOnline(Int64 tid)
{
using (var wc = new WebClient())
{
return wc.DownloadString("https://data.mtgox.com/api/1/BTCUSD/trades?since=" + tid.ToString());
}
}
另外2个POST示例
// POST
string SubmitData(string data)
{
string response;
using (var wc = new WebClient())
{
wc.Headers["Content-type"] = "text/plain";
response = wc.UploadString("https://data.mtgox.com/api/1/BTCUSD/trades", "POST", data);
}
return response;
}
// POST: easily url encode multiple parameters
string SubmitForm(string project, string subject, string sender, string message)
{
// url encoded query
NameValueCollection query = HttpUtility.ParseQueryString(string.Empty);
query.Add("project", project);
query.Add("subject", subject);
// url encoded data
NameValueCollection data = HttpUtility.ParseQueryString(string.Empty);
data.Add("sender", sender);
data.Add("message", message);
string response;
using (var wc = new WebClient())
{
wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
response = wc.UploadString( "https://data.mtgox.com/api/1/BTCUSD/trades?"+query.ToString()
, WebRequestMethods.Http.Post
, data.ToString()
);
}
return response;
}
错误处理
try
{
Console.WriteLine(GetTradesOnline(0));
string data = File.ReadAllText(@"C:\mydata.txt");
Console.WriteLine(SubmitData(data));
Console.WriteLine(SubmitForm("The Big Project", "Progress", "John Smith", "almost done"));
}
catch (WebException ex)
{
string msg;
if (ex.Response != null)
{
// read response HTTP body
using (var sr = new StreamReader(ex.Response.GetResponseStream())) msg = sr.ReadToEnd();
}
else
{
msg = ex.Message;
}
Log(msg);
throw; // re-throw without changing the stack trace
}