Question

我想在我的网站上的一些div中添加5个即将到来的日期名称。我为日名创建了数组，然后我从中调用了值并添加了天数。该方法仅适用于第一天，然后数组结束，从第2天到第5天它回应“未定义”。

请帮忙吗？

var weekday=new Array(7);
weekday[0]="Nedelja";
weekday[1]="Ponedeljek";
weekday[2]="Torek";
weekday[3]="Sreda";
weekday[4]="Četrtek";
weekday[5]="Petek";
weekday[6]="Sobota";
var dan = weekday[today.getDay()];

var dan_1 = weekday[today.getDay()+1];
document.getElementById("day1").innerHTML = dan_1;
var dan_2 = weekday[today.getDay()+2];
document.getElementById("day2").innerHTML = dan_2;
var dan_3 = weekday[today.getDay()+3];
document.getElementById("day3").innerHTML = dan_3;
var dan_4 = weekday[today.getDay()+4];
document.getElementById("day4").innerHTML = dan_4;
var dan_5 = weekday[today.getDay()+5];
document.getElementById("day5").innerHTML = dan_5;

谢谢你们！

Answer 1

嗯，你需要％7和7（一周中的天数）

var weekday=new Array(7);
weekday[0]="Nedelja";
weekday[1]="Ponedeljek";
weekday[2]="Torek";
weekday[3]="Sreda";
weekday[4]="Četrtek";
weekday[5]="Petek";
weekday[6]="Sobota";
var dan = weekday[today.getDay()%7];

var dan_1 = weekday[(today.getDay()+1)%7];
document.getElementById("day1").innerHTML = dan_1;
var dan_2 = weekday[(today.getDay()+2)%7];
document.getElementById("day2").innerHTML = dan_2;
var dan_3 = weekday[(today.getDay()+3)%7];
document.getElementById("day3").innerHTML = dan_3;
var dan_4 = weekday[(today.getDay()+4)%7];
document.getElementById("day4").innerHTML = dan_4;
var dan_5 = weekday[(today.getDay()+5)%7];
document.getElementById("day5").innerHTML = dan_5;

例如：如果today.getDay()返回5，则接下来的5天是10，这在您的数组中不存在。当你％7时，你会回到3（下周）

Answer 2

您可以在数组访问中添加模%运算，以防止溢出并在开头重新启动：

// ...
var dan_1 = weekday[(today.getDay()+1)%7];
document.getElementById("day1").innerHTML = dan_1;
var dan_2 = weekday[(today.getDay()+2)%7];
document.getElementById("day2").innerHTML = dan_2;
var dan_3 = weekday[(today.getDay()+3)%7];
document.getElementById("day3").innerHTML = dan_3;
var dan_4 = weekday[(today.getDay()+4)%7];
document.getElementById("day4").innerHTML = dan_4;
var dan_5 = weekday[(today.getDay()+5)%7];
document.getElementById("day5").innerHTML = dan_5;

Example Fiddle

Answer 3

你的问题是以合乎逻辑的方式推进这一天。这是通过添加到当前日期并从除法中选择余数（模数，%）来实现的。请参阅下面代码中的(dan + i) % 7部分。

我将使用Khanh TO’s answer中已修复的代码并以更简洁的方式编写代码。现在你的代码有点重复，这可以通过使用数组文字和循环来帮助。

var today = new Date();
var weekday = ["Nedelja","Ponedeljek","Torek","Sreda","Četrtek","Petek","Sobota"];
var dan = today.getDay();
for (var i = 1; i <= 5; i++) {
    var elem = document.getElementById("day" + i);
    elem.innerHTML = weekday[(dan + i) % 7];
}

我相信看到更优雅的风格对你有好处。

JavaScript可以获得带有单词的日子，比当前日期有五天

3 个答案: