如何将文字拆分成文字?
示例文字:
“哦,你无能为力,”猫说:“我们都疯了。我生气了。你生气了。'
该行中的文字是:
答案 0 :(得分:36)
在空格上拆分文字,然后修剪标点符号。
var text = "'Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad.'";
var punctuation = text.Where(Char.IsPunctuation).Distinct().ToArray();
var words = text.Split().Select(x => x.Trim(punctuation));
完全赞同例子。
答案 1 :(得分:23)
首先,删除所有特殊字符:
var fixedInput = Regex.Replace(input, "[^a-zA-Z0-9% ._]", string.Empty);
// This regex doesn't support apostrophe so the extension method is better
然后分开它:
var split = fixedInput.Split(' ');
对于更简单的C#解决方案来删除特殊字符(您可以轻松更改),请添加此扩展方法(我添加了对撇号的支持):
public static string RemoveSpecialCharacters(this string str) {
var sb = new StringBuilder();
foreach (char c in str) {
if ((c >= '0' && c <= '9') || (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || c == '\'' || c == ' ') {
sb.Append(c);
}
}
return sb.ToString();
}
然后像这样使用它:
var words = input.RemoveSpecialCharacters().Split(' ');
你会惊讶地知道这种扩展方法非常有效(肯定比正则表达式更有效)所以我建议你使用它;)
<强>更新强>
我同意这是一种仅限英语的方法,但要使其兼容Unicode,您只需要替换:
(c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z')
使用:
char.IsLetter(c)
哪个支持Unicode,。。还为各种案例提供char.IsSymbol
和char.IsLetterOrDigit
答案 2 :(得分:6)
只是为@Adam Fridental的答案添加一个非常好的答案,你可以试试这个正则表达式:
var text = "'Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad.'";
var matches = Regex.Matches(text, @"\w+[^\s]*\w+|\w");
foreach (Match match in matches) {
var word = match.Value;
}
我相信这是最短的RegEx,可以获得所有的单词
\w+[^\s]*\w+|\w
答案 3 :(得分:1)
如果您不想使用Regex对象,可以执行类似......
的操作string mystring="Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad.";
List<string> words=mystring.Replace(",","").Replace(":","").Replace(".","").Split(" ").ToList();
你仍然需要在“那个”
的末尾处理尾随撇号答案 4 :(得分:1)
这是解决方案之一,我不使用任何辅助类或方法。
public static List<string> ExtractChars(string inputString) {
var result = new List<string>();
int startIndex = -1;
for (int i = 0; i < inputString.Length; i++) {
var character = inputString[i];
if ((character >= 'a' && character <= 'z') ||
(character >= 'A' && character <= 'Z')) {
if (startIndex == -1) {
startIndex = i;
}
if (i == inputString.Length - 1) {
result.Add(GetString(inputString, startIndex, i));
}
continue;
}
if (startIndex != -1) {
result.Add(GetString(inputString, startIndex, i - 1));
startIndex = -1;
}
}
return result;
}
public static string GetString(string inputString, int startIndex, int endIndex) {
string result = "";
for (int i = startIndex; i <= endIndex; i++) {
result += inputString[i];
}
return result;
}
答案 5 :(得分:0)
您可以尝试使用正则表达式删除未被字母(即单引号)包围的撇号,然后使用Char
静态方法去除所有其他字符。通过首先调用正则表达式,您可以保留缩减撇号(例如can't
),但删除'Oh
中的单引号。
string myText = "'Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad.'";
Regex reg = new Regex("\b[\"']\b");
myText = reg.Replace(myText, "");
string[] listOfWords = RemoveCharacters(myText);
public string[] RemoveCharacters(string input)
{
StringBuilder sb = new StringBuilder();
foreach (char c in input)
{
if (Char.IsLetter(c) || Char.IsWhiteSpace(c) || c == '\'')
sb.Append(c);
}
return sb.ToString().Split(' ');
}
答案 6 :(得分:0)
如果要使用“ for cycle”检查每个字符并在输入字符串中保存所有标点符号,我已经创建了此类。方法GetSplitSentence()返回SentenceSplitResult的列表。在此列表中,保存了所有单词以及所有标点符号和数字。保存的每个标点符号或数字都是列表中的一项。句子SplitResult.isAWord用于检查是否为单词。 [对不起,我的英语]
public class SentenceSplitResult
{
public string word;
public bool isAWord;
}
public class StringsHelper
{
private readonly List<SentenceSplitResult> outputList = new List<SentenceSplitResult>();
private readonly string input;
public StringsHelper(string input)
{
this.input = input;
}
public List<SentenceSplitResult> GetSplitSentence()
{
StringBuilder sb = new StringBuilder();
try
{
if (String.IsNullOrEmpty(input)) {
Logger.Log(new ArgumentNullException(), "GetSplitSentence - input is null or empy");
return outputList;
}
bool isAletter = IsAValidLetter(input[0]);
// Each char i checked if is a part of a word.
// If is YES > I can store the char for later
// IF is NO > I Save the word (if exist) and then save the punctuation
foreach (var _char in input)
{
isAletter = IsAValidLetter(_char);
if (isAletter == true)
{
sb.Append(_char);
}
else
{
SaveWord(sb.ToString());
sb.Clear();
SaveANotWord(_char);
}
}
SaveWord(sb.ToString());
}
catch (Exception ex)
{
Logger.Log(ex);
}
return outputList;
}
private static bool IsAValidLetter(char _char)
{
if ((Char.IsPunctuation(_char) == true) || (_char == ' ') || (Char.IsNumber(_char) == true))
{
return false;
}
return true;
}
private void SaveWord(string word)
{
if (String.IsNullOrEmpty(word) == false)
{
outputList.Add(new SentenceSplitResult()
{
isAWord = true,
word = word
});
}
}
private void SaveANotWord(char _char)
{
outputList.Add(new SentenceSplitResult()
{
isAWord = false,
word = _char.ToString()
});
}