Question

我有一些代码在Linux上使用iconv（）来验证字符串是否为UTF-8编码。我创建的转换如下：

iconv_t c = iconv_open("UTF-8","UTF-8");

我运行iconv（），如：

int status = iconv(c, &fromArray, (size_t*)&inSize, &toArray, (size_t*)&outSize);

如果status不是-1，我会将字符串设置为有效的UTF-8。

这在32位环境（最初开发和测试）中编译并正常工作。但是我现在要求在64位环境中工作（特别是我相信的64位Fedora 14的味道）。当我编译并运行测试时，status始终为-1，我总是在EILSEQ中出现errno错误，即使对于32位编译的相同字符串也是如此说没关系。

有没有人对为什么会发生这种情况有任何想法？

Answer 1

最近遇到过同样的问题。转换为（size_t *）更多（非常）可能是根本原因。使用下一个代码可以轻松模拟问题：

cat >Makefile <<EOF
all: build test clean

clean:
    rm -f *.o core* t32 t64
test: build
    @echo ; echo "run_32bit version:" ; ./t32
    @echo ; echo "run_64bit version:" ; ./t64
build:
    g++ -m32 t.cpp -o t32 -Wall -O0 -g
    g++      t.cpp -o t64 -Wall -O0 -g
EOF

cat >t.cpp <<EOF
#include <errno.h>
#include <stdio.h>
#include <iconv.h>

char buff_toArray [BUFSIZ];
char buff_fromArray [] = \
"<TESTS_STRINGS>\
    <T_VERIFICATION_STRINGS/>\
</TESTS_STRINGS>";

void iconv_test ( const char* desc, size_t* size )
{
   printf ("%s = size[%zu]\n",desc, (*size) );
}

int main (int argc, char* argv[])
{

 char* toArray = &buff_toArray[0];
 char* fromArray = &buff_fromArray[0];

 const int inSize_const = 61;
 short inSize_short = (short) sizeof(buff_fromArray);
 int inSize_int = (int) sizeof(buff_fromArray);
 unsigned int inSize_uint = (unsigned int) sizeof(buff_fromArray);
 long inSize_long = (long) sizeof(buff_fromArray);
 long long inSize_llong = (long long) sizeof(buff_fromArray);
 size_t inSize_size_t = sizeof(buff_fromArray);

 printf ("fake iconv usage:\n");
 iconv_test((const char*) "inSize_const", (size_t*)&inSize_const);
 iconv_test((const char*) "inSize_short", (size_t*)&inSize_short);
 iconv_test((const char*) "inSize_int", (size_t*)&inSize_int);
 iconv_test((const char*) "inSize_uint", (size_t*)&inSize_uint);
 iconv_test((const char*) "inSize_long", (size_t*)&inSize_long);
 iconv_test((const char*) "inSize_llong", (size_t*)&inSize_llong);
 iconv_test((const char*) "inSize_size_t", &inSize_size_t);

 printf ("real iconv usage:\n");
 int inSize = sizeof(buff_fromArray);
 int outSize = sizeof(buff_toArray);

 iconv_t c = iconv_open("UTF-8","UTF-8");
 int status = iconv(c, &fromArray, (size_t*)&inSize, &toArray, (size_t*)&outSize);
 printf ("status=[%d], errno=[%d] \n", status, errno );

 printf ("result string:\n");
 for(size_t i = 0; i <= sizeof(buff_toArray); i++) { printf ("%c", buff_toArray[i]); }
 printf ("\n");

 int close_status =  iconv_close(c);
 printf ("close status=[%d], errno=[%d] \n", close_status, errno );

 return 0;
}
EOF

iconv（）在Linux上为32位与64位

1 个答案: