Question

我正在尝试执行一个从java传递4个参数的bash脚本。我可以使用以下代码完美地执行没有参数的脚本：



    try 
        {       
            String command = "bash bash/testbash.sh";
            Runtime run = Runtime.getRuntime();
            Process pr = run.exec(command);
            pr.waitFor();
            BufferedReader buf = new BufferedReader(new InputStreamReader(pr.getInputStream()));
            String line = "";
            while ((line=buf.readLine())!=null) 
            {
                System.out.println(line);
            }
         }  
        catch (Exception e) 
        {  
            System.out.println("Exception " + e);
            e.printStackTrace();
        }  
    }

try { String command = "bash bash/testbash.sh"; Runtime run = Runtime.getRuntime(); Process pr = run.exec(command); pr.waitFor(); BufferedReader buf = new BufferedReader(new InputStreamReader(pr.getInputStream())); String line = ""; while ((line=buf.readLine())!=null) { System.out.println(line); } } catch (Exception e) { System.out.println("Exception " + e); e.printStackTrace(); } }

所以我打算让String []将命令和参数传递给Runtime.exec（），如下所示：

    try 
        {       
            String[] command ={"bash bash/testbash.sh"};
            Runtime run = Runtime.getRuntime();
            Process pr = run.exec(command);
            pr.waitFor();
            BufferedReader buf = new BufferedReader(new InputStreamReader(pr.getInputStream()));
            String line = "";
            while ((line=buf.readLine())!=null) 
            {
                System.out.println(line);
            }
         }  
        catch (Exception e) 
        {  
            System.out.println("Exception " + e);
            e.printStackTrace();
        }  
    }

这给了我这个错误： try { String[] command ={"bash bash/testbash.sh"}; Runtime run = Runtime.getRuntime(); Process pr = run.exec(command); pr.waitFor(); BufferedReader buf = new BufferedReader(new InputStreamReader(pr.getInputStream())); String line = ""; while ((line=buf.readLine())!=null) { System.out.println(line); } } catch (Exception e) { System.out.println("Exception " + e); e.printStackTrace(); } }

这对我没有意义。 bash文件显然存在，因为我只是将它与String命令一起使用，但是当我在String []命令中使用相同的东西时它不存在？我如何通过参数传递命令？

Answer 1

String [] command = {“bash bash / testbash.sh”};

String[] command ={"bash", "bash/testbash.sh"};

使用带有String []的Runtime.exec（）

1 个答案: