Question

你好，所以我的PHP脚本给我一个错误，我的if语句的右括号错误如下，这极大地阻碍了我，任何帮助将不胜感激。

解析错误：语法错误，第40行意外的T_ELSE

if($numrows !=0) {
    while ($rows = mysql_fetch_assoc($query)) {
        $dbusername = $row['username'];
        $dbpassword = $row['password'];
    }

    if ($username==$dbusername&&$password==dbpassword) {
        echo "Login Successful. <a href='homepage.html'>Click Here to go to the home page</a>";
        $_SESSION['username']=$dbusername;
    }

    else {
        echo "Incorrect Login";
    }

    else {
        die ("This account does not exsist");
    }

    else {
        die ("Please enter a username and password");
    }
}

Answer 1

您有 3 else，我只看到 2 if。

在需要的地方尝试else if (condtion){ }，或者只是将所有代码放在一个else中。

目前，这些else没有匹配if并生成Parse error: syntax error, unexpected T_ELSE on line 40

else{
die ("This account does not exsist");
    }

else{
die ("Please enter a username and password");

Answer 2

你必须使用elseif

请通过：http://php.net/manual/en/control-structures.elseif.php

例如：

if ($numrows != 0) {
  while ($rows = mysql_fetch_assoc($query)) {
    $dbusername = $row['username'];
    $dbpassword = $row['password'];
  }
  if ($username == $dbusername && $password == dbpassword) {
    echo "Login Successful. <a href='homepage.html'>Click Here to go to the home page</a>";
    $_SESSION['username'] = $dbusername;
  } elseif ($username == '' || $password == '') {
    die("Please enter a username and password");
  } elseif (empty($dbusername)) {
    die("This account does not exsist");
  } else {
    die("Please enter a username and password");
  }
}

PHP Brackets错误麻烦

2 个答案: