Question

我有函数测试，它返回属于单独类

的静态函数staticABC的repsonse

function test()
{
   return testA::staticABC();
}

现在我想通过模拟staticABC（）函数来编写用于函数测试的PHPUnit案例。任何技术人员都可以对此有所了解吗？

Answer 1

我不认为有一种模拟函数的方法，但你可以做的是使用某种test double：

class SUT{
    $staticCreator = array('testA::staticABC'); //Initialized to a default 
             //for production, would be better if injected somehow before using

    function setStaticCreator($staticCreator){
        $this->staticCreator=$staticCreator;
    }
    function test(){
        return call_user_func($this->staticCreator);
    }
}

然后以这种方式运行测试：

class Test extends ...{
    function mockStaticABC(){
        return "mock_string";
    }

    test_testfunction(){
        $sut = new SUT();
        $staticCreator = array($this,'mockStaticABC');
        $sut->setStaticCreator($staticCreator);
        $mock_return = $sut->test();
        $this->assertEquals("mock_string",$mock_return);
    }
}

嘲笑一个单独的类的功能

1 个答案: