Question

我想在函数中调用按钮事件，如下所示，这可能不是正确的方法。如果你知道如何解决这个问题，请分享一些如何实现它的样本。感谢

 protected override bool ProcessCmdKey(ref Message msg, Keys keyData) 
    {
        const int WM_KEYDOWN = 0x100;
        const int WM_SYSKEYDOWN = 0x104;

        if ((msg.Msg == WM_KEYDOWN) || (msg.Msg == WM_SYSKEYDOWN))
        {
            switch (keyData)
            {
              case Keys.Down:
              button4_Click(sender, e); //error: sender and e does not exist in the current context
              break;
            }
        }

        return base.ProcessCmdKey(ref msg, keyData);
    }

Answer 1

试试这个：

protected override bool ProcessCmdKey(ref Message msg, Keys keyData) 
{
    const int WM_KEYDOWN = 0x100;
    const int WM_SYSKEYDOWN = 0x104;

    if ((msg.Msg == WM_KEYDOWN) || (msg.Msg == WM_SYSKEYDOWN))
    {
        switch (keyData)
        {
          case Keys.Down:
          button4_Click(null, null);
          break;
        }
    }

    return base.ProcessCmdKey(ref msg, keyData);
}

Answer 2

为什么不将button4_Click代码移动到ProcessSomething()等其他方法并在那里进行处理。然后只需更改

protected override bool ProcessCmdKey(ref Message msg, Keys keyData) 
{
    const int WM_KEYDOWN = 0x100;
    const int WM_SYSKEYDOWN = 0x104;

    if ((msg.Msg == WM_KEYDOWN) || (msg.Msg == WM_SYSKEYDOWN))
    {
        switch (keyData)
        {
          case Keys.Down:
          ProcessSomething();
          break;
        }
    }

    return base.ProcessCmdKey(ref msg, keyData);
}

您可以通过向其传递空值来触发button4_Click方法，但是IMO对此类事件进行触发并不优雅。

Answer 3

调用button4 click将自己作为发件人传递，将新System EventArgs作为第二个参数传递：

button4_Click(button4, new System.EventArgs());

从函数中调用按钮事件

3 个答案: