计算有多少行具有相同的值

Question

如何编写SQL查询来计算表格num列中特定num值的总数。

e.g。选择num = 1

的位置

结果：2

+-----+-----+
| NAME | NUM |
+=====+=====+
| SAM  |  1  | 
+-----+-----+
| BOB  |  1  |
+-----+-----+
| JAKE |  2  | 
+-----+-----+  
| JOHN |  4  | 
+-----+-----+

Answer 1

尝试

SELECT NAME, count(*) as NUM FROM tbl GROUP BY NAME

的 SQL FIDDLE

Answer 2

如果您想获得NUM的所有值的结果：

SELECT `NUM`, COUNT(*) AS `count` 
FROM yourTable
GROUP BY `NUM`

或仅针对一个特定的：

SELECT `NUM`, COUNT(*) AS `count` 
FROM yourTable
WHERE `NUM`=1

Answer 3

FOR SPECIFIC NUM：

SELECT COUNT(1) FROM YOUR_TABLE WHERE NUM = 1

FOR ALL NUM：

SELECT NUM, COUNT(1) FROM YOUR_TABLE GROUP BY NUM

Answer 4

SELECT 
   COUNT(NUM) as 'result' 
FROM 
   Table1 
GROUP BY 
   NUM 
HAVING NUM = 1

Answer 5

尝试此查询

select NUM, count(1) as count 
from tbl 
where num = 1
group by NUM
--having count(1) (You condition)

<强> SQL FIDDLE

Answer 6

SELECT sum(num) WHERE num = 1;

Answer 7

SELECT SUM(IF(num=1,1,0)) FROM your_table_name;

e.g。为您查询： -

Selector(("handleGetURLEvent:replyEvent:"))

Answer 8

使用此查询，将给出您的输出：

select 
  t.name
  ,( select 
       count (*) as num_value 
     from Table 
      where num =t.num) cnt 
from Table t;