Question

EDITED

我需要执行一个只带给我 user_id 的查询，他的所有手机确认= 2 ，而不仅仅是一两个，必须全部都是

我的表格如下：

 id      user_id    phone        confirmed
 ------- --------   -----------  ---
 1       1          3051234561   1
 1       1          3051234562   0
 1       1          3051234563   2
 1       2          3051234564   2
 1       2          3051234565   2
 1       2          3051234566   2
 1       3          3051234567   0
 1       3          3051234568   1
 1       4          3051234569   1

在这种情况下，必须返回user_id 2

我试图用GROUP HAVING做这件事，但我没有得到我需要的结果。例如：

SELECT
*
FROM
    phones
GROUP BY 
    user_id
HAVING 
    MAX(confirmed) = 2

Answer 1

试试这个

SELECT distinct user_id FROM phones GROUP BY user_id HAVING sum(confirmed) = 2 * count(confirmed)

这将为所有未确认电话的user_id提供

Answer 2

尝试此查询 -

SELECT
 user_id
FROM
  phones
GROUP BY 
  user_id
HAVING 
  COUNT(IF(confirmed = 2, 1, NULL)) = COUNT(*)

输出：

+---------+
| user_id |
+---------+
|       2 |
+---------+

Answer 3

在WHERE

之前，您需要GROUP BY条件

Answer 4

尝试以下内容....

   "SELECT * FROM phones WHERE confirmed='0' GROUP BY user_id"

Answer 5

尝试这个

SELECT *
FROM phones
Where confirmed= 0
GROUP BY user_id

Answer 6

您可以尝试这样

SELECT user_id FROM phones WHERE confirmed=0 GROUP BY user_id;

Answer 7

SELECT distinct user_id FROM phones GROUP BY user_id HAVING sum（confirm）= 0

您写道：

SELECT
*
FROM
    phones
GROUP BY 
    user_id
HAVING 
    MAX(confirmed) = 2

现在你需要所有确认为0，得到它们的总和必须为零，并且你不想要所有属性而是user_id：

SELECT
    distinct(user_id)
FROM
    phones
GROUP BY 
    user_id
HAVING 
    SUM(confirmed) = 0

MySQL所有只匹配字段值的行

7 个答案: