Question

快速提问...我有一个查询，检查看起来像这样的重复项：

 SELECT COUNT( * ) AS repetitions, Name, Phone, ID, categoryid, State
 FROM users 
 GROUP BY Name, Phone, State
 HAVING repetitions > 1 
 ORDER BY ID DESC

这可行，但MySQL返回一组重复项中的第一个ID。例如，假设我有2行。第一行的ID为1，第二行的ID为2，名称，电话和状态具有相同的数据...如何使上述查询返回计数但ID为“2”而不是“1”？ / p>

谢谢！ ;）

Answer 1

使用max（）聚合函数：

SELECT COUNT(*) AS repetitions, max(ID) FROM users GROUP BY Name, Phone, State HAVING repetitions > 1 ORDER BY ID DESC

Answer 2

不完美但有效

SELECT COUNT( * ) AS repetitions, Name, Phone, MAX(ID), categoryid, State 
FROM users 
GROUP BY Name, Phone, State 
HAVING repetitions > 1

MySQL中的最后一项COUNT（*）结果？

2 个答案: