d3.js组合图表Line和Scatter

时间:2013-05-22 20:49:09

标签: d3.js

我对d3.js很新,我试图在散点图上添加一条线。我有两个要绘制的数据集

var data = [ {
        "x" : 30,
        "y" : 30,
        "r" : 20,
        "c" : "green",
        "s" : "s1"
    }, {
        "x" : 70,
        "y" : 70,
        "r" : 20,
        "c" : "purple",
        "s" : "s2"
    }, {
        "x" : 110,
        "y" : 100,
        "r" : 20,
        "c" : "red",
        "s" : "s3"
    } ];

    var data1 = [{
        "x":30,
        "y":30},
        {"x":70,
            "y":70}];

数据变量用作散点图系列,在同一图表上我想将第二个数据集绘制为线系列。

var margin = {
            top : 20,
            right : 20,
            bottom : 30,
            left : 40
        }, width = 960 - margin.left - margin.right, height = 500 - margin.top
                - margin.bottom;

    var x = d3.scale.linear().range([ 0, width ]);

    var y = d3.scale.linear().range([ height, 0 ]);

    var color = d3.scale.category10();

    var xAxis = d3.svg.axis().scale(x).orient("bottom");

    var yAxis = d3.svg.axis().scale(y).orient("left");

    var svg = d3.select("#"+div).append("svg").attr("width",
            width + margin.left + margin.right).attr("height",
            height + margin.top + margin.bottom).append("g").attr(
            "transform",
            "translate(" + margin.left + "," + margin.top + ")");

    var data = [ {
        "x" : 30,
        "y" : 30,
        "r" : 20,
        "c" : "green",
        "s" : "s1"
    }, {
        "x" : 70,
        "y" : 70,
        "r" : 20,
        "c" : "purple",
        "s" : "s2"
    }, {
        "x" : 110,
        "y" : 100,
        "r" : 20,
        "c" : "red",
        "s" : "s3"
    } ];

    var data1 = [{
        "x":30,
        "y":30},
        {"x":70,
            "y":70}];

    x.domain(d3.extent(data, function(d) {          
        return d.x;
    })).nice();
    y.domain(d3.extent(data, function(d) {
        return d.y;
    })).nice();

    svg.append("g").attr("class", "x axis").attr("transform",
            "translate(0," + height + ")").call(xAxis).append("text").attr(
            "class", "label").attr("x", width).attr("y", -6).style(
            "text-anchor", "end").text("Yield");

    svg.append("g").attr("class", "y axis").call(yAxis).append("text")
            .attr("class", "label").attr("transform", "rotate(-90)").attr(
                    "y", 6).attr("dy", ".71em").style("text-anchor", "end")
            .text("Skew")

    var line = d3.svg.line()
            .x(function(d) { return x(d.x); })
            .y(function(d) { return y(d.y); });
    svg.selectAll(".line").data(data1).enter().append("path").attr("class","line").attr("d",line);

    svg.selectAll(".dot").data(data).enter().append("circle").attr("class",
            "dot").attr("r", 3.5).attr("cx", function(d) {
        return x(d.x);
    }).attr("cy", function(d) {
        return y(d.y);
    }).style("fill", function(d) {
        return color(d.c);
    });



    var legend = svg.selectAll(".legend").data(color.domain()).enter()
            .append("g").attr("class", "legend").attr("transform",
                    function(d, i) {
                        return "translate(0," + i * 20 + ")";
                    });

    legend.append("rect").attr("x", width - 18).attr("width", 18).attr(
            "height", 18).style("fill", color);

    legend.append("text").attr("x", width - 24).attr("y", 9).attr("dy",
            ".35em").style("text-anchor", "end").text(function(d) {
        return d;
    });

但我根本没有看到画线。

1 个答案:

答案 0 :(得分:2)

使用数据([data1])(或数据(data1))并为该线条设置样式使其显示:

svg.append("path")
        .data([data1])
    .attr("class","line")
    .attr("stroke", "steelblue")
    .attr("fill", "none")
    .attr("stroke-width", 1.5)
    .attr("d",line);

之前:

svg.selectAll(".line").
        data(data1).enter()
    .append("path")
        .attr("class","line")
        .attr("d",line);

正在为您想要绘制的每个点创建一个路径元素。

<path class="line"></path>
<path class="line"></path>

并且线路从未被调用过。相反,我们需要一个路径对象,其中整个点数组绑定到它。使用该对象,我们使用.attr(“d”,line)添加点,最后得到:

<path class="line" stroke-width="1.5" d="M0,450L450,192.8571428571429"></path> 

通过mbostock(及其链接)查看此post,了解有关为什么的更多信息。