为什么VC2012编译器进入堆栈溢出(错误C1063)?

时间:2013-05-22 13:03:00

标签: visual-c++ stl compiler-errors iterator stack-overflow

我有自己的工作迭代器来水平或垂直地覆盖图像中的像素。通过模板参数,它可以是const或不是Dr. Dobb's的整洁技巧。)

然后我意识到有一个std::iterator基类,我认为我会让我的东西更多 STLly 并继承它。

不幸的是,现在 Visual Studio 2012 (版本11.0.60315.01更新2)将不再编译它。我实际上设法得到编译器stackoverflow。这是消息:

  

错误1错误C1063:编译器限制:编译器堆栈溢出d:\ ... \ source.cpp 42 1 ConsoleApplication3

我课程的一个非常精简的版本看起来像这样:

#include <iterator>

// This comes from the outer image class.
typedef float color_type;

template<bool IS_CONST = false>
struct Iterator : public std::iterator<std::random_access_iterator_tag, color_type>
{
    // This is myself...
    typedef Iterator<IS_CONST> iterator;
    // ... and my variants.
    typedef Iterator<true> const_iterator;
    typedef std::reverse_iterator<iterator> reverse_iterator;
    typedef std::reverse_iterator<const_iterator> const_reverse_iterator;

    // Make base class typedefs available.
    typedef typename iterator::value_type value_type;
    typedef typename iterator::difference_type difference_type;

    // My own typedefs to deal with immutability.
    typedef value_type const & const_reference;
    typedef typename std::conditional<IS_CONST, const_reference, typename iterator::reference>::type reference;

    Iterator()
        : _position(nullptr),
        _step()
    {
    }

    Iterator(value_type * const position, difference_type const step)
        : _position(position),
        _step(step)
    {
    }

    iterator const operator-(difference_type n) const
    {
        return iterator(*this) -= n;
    }

    difference_type operator-(iterator const rhs) const
    {
        assert(_step == rhs._step);
        return (_position - rhs._position) / _step;
    }

protected:
    value_type * _position;
    difference_type _step;
};

int main()
{
    float a = 3.141f;
    // Instanciate all variants.
    Iterator<false> empty;
    Iterator<true> const_empty;
    Iterator<false> some(&a, 5);
    Iterator<true> const_some(&a, 5);
    return 0;
}

删除两个operator-中的任何一个使编译器满意。

有人可以告诉我这里的问题是什么吗?或者甚至更好地为它提供修复?

由于


更新:哦,顺便说一句,GCC 4.7.2 happily compiles it

2 个答案:

答案 0 :(得分:3)

最小例子:

template<bool B>
struct Iterator
{
    typedef typename Iterator<B>::some_type some_type ;

    int foo();

    int foo(some_type n);
};

int main()
{
    return 0;
}

http://rise4fun.com/Vcpp/2eQ的输出:

testvc.cpp(1) : info : Could not find CompilerVersion hint, using default compiler version 'VS2012CTP'
testvc.cpp(1) : info : Ignoring directive '#include', which cannot be used in this online version of the Visual C++ compiler
testvc.cpp(1) : info : Automatically importing the Standard Library headers which match this online version of the Visual C++ compiler
Microsoft (R) C/C++ Optimizing Compiler Version 17.00.51025 for x86
Copyright (C) Microsoft Corporation.  All rights reserved.

testvc.cpp
--\testvc.cpp(10) : fatal error C1063: compiler limit : compiler stack overflow
        --\testvc.cpp(11) : see reference to class template instantiation 'Iterator' being compiled
Internal Compiler Error in .  You will be prompted to send an error report to Microsoft later.

要解决此问题,请从代码中删除以下行:

// Make base class typedefs available.
typedef typename iterator::value_type value_type;
typedef typename iterator::difference_type difference_type;

然后在Visual C ++(http://rise4fun.com/Vcpp/1pg)中编译:

testvc.cpp(1) : info : Could not find CompilerVersion hint, using default compiler version 'VS2012CTP'
testvc.cpp(1) : info : Ignoring directive '#include', which cannot be used in this online version of the Visual C++ compiler
testvc.cpp(1) : info : Automatically importing the Standard Library headers which match this online version of the Visual C++ compiler
testvc.cpp(2) : info : Ignoring directive '#include', which cannot be used in this online version of the Visual C++ compiler
Microsoft (R) C/C++ Optimizing Compiler Version 17.00.51025 for x86
Copyright (C) Microsoft Corporation.  All rights reserved.

testvc.cpp
testvc.cpp(64) : info : File compiled with no errors!

并在GCC(http://ideone.com/mEX18H)中按预期工作:

result: Success     time: 0s    memory: 2896 kB     returned value: 0 
input: no

output:
0 0

答案 1 :(得分:1)

哦,我的,那是愚蠢的...和jerry's answer一起玩我让我发现了自己的错误。当然编译器会进入递归,从而导致堆栈溢出。我写的时候

// Make base class typedefs available.
typedef typename iterator::value_type value_type;
typedef typename iterator::difference_type difference_type;

我的目的是让基类“typedef易于使用。但是,在没有任何资格的情况下编写iterator是指班级本身,感谢我上面的其他typedef duh!

// This is myself...
typedef Iterator<IS_CONST> iterator;

因此,通过正确引用iterator中的std,问题就解决了我可以保留typedef

// Make base class typedefs available.
typedef std::iterator<std::random_access_iterator_tag, color_type> base_class;
typedef typename base_class::value_type value_type;
typedef typename base_class::difference_type difference_type;

有趣的是,GCC似乎没有问题。