我正在尝试构建一个函数,以便在tweet中找到hashtags
。用HTML <a> tag
围绕它们。这样我就可以链接到他们了。这就是我的工作。
NSError* error = nil;
NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:@"(?:\\s|\\A)[##]+([A-Za-z0-9-_]+)" options:0 error:&error];
NSArray* matches = [regex matchesInString:tweetText options:0 range:NSMakeRange(0, [tweetText length])];
for ( NSTextCheckingResult* match in matches )
{
NSString* matchText = [tweetText substringWithRange:[match range]];
NSString *matchText2 = [matchText stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSString *search = [matchText2 stringByReplacingOccurrencesOfString:@"#"
withString:@""];
NSString *searchHTML= [NSString stringWithFormat:@"<a href='https://twitter.com/search?q=%%23%@'>%@</a>",search,matchText];
tweetText = [tweetText stringByReplacingOccurrencesOfString:matchText
withString:searchHTML];
NSLog(@"match: %@", tweetText);
}
在执行此函数之前,tweetText循环通过另一个函数来查找URL。所以推文可以包含以下内容。 <a href='http://google.be' target='_blank'>http://google.be</a>
现在有时它会在其他链接周围放置另一个标记,而不仅仅是在主题标签周围。
有人可以帮我这个吗?
提示
我正在尝试将以下JAVA代码转换为OBJ-C
String patternStr = "(?:\\s|\\A)[##]+([A-Za-z0-9-_]+)"
Pattern pattern = Pattern.compile(patternStr)
Matcher matcher = pattern.matcher(tweetText)
String result = "";
// Search for Hashtags
while (matcher.find()) {
result = matcher.group();
result = result.replace(" ", "");
String search = result.replace("#", "");
String searchHTML="<a href='http://search.twitter.com/search?q=" + search + "'>" + result + "</a>"
tweetText = tweetText.replace(result,searchHTML);
}
修改
Gers, we kijken er al naar uit! “@GersPardoel: We zitten in België straks naar Genk!!<a href='<a href<a href='https://twitter.com/search?q=%23='http'>='http</a>s://twitter.com/search?q=%23https:/'>https:/</a>/twitter.com/search?q=%23engaan'> #engaan</a>” #GOS12 #genk #fb
答案 0 :(得分:1)
问题是,当您循环匹配时,您正在修改tweetText
变量(tweetText = ...
)。想象一下下次代码进入循环时会发生什么?由于substringWithRange
是在原始字符串上创建的,因此NSError* error = nil;
NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:@"(?:\\s|\\A)[##]+([A-Za-z0-9-_]+)" options:0 error:&error];
NSArray* matches = [regex matchesInString:tweetText options:0 range:NSMakeRange(0, [tweetText length])];
NSString* processedString = [[tweetText copy] autorelease];
for ( NSTextCheckingResult* match in matches )
{
NSString* matchText = [tweetText substringWithRange:[match range]];
NSString *matchText2 = [matchText stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSString *search = [matchText2 stringByReplacingOccurrencesOfString:@"#"
withString:@""];
NSString *searchHTML= [NSString stringWithFormat:@"<a href='https://twitter.com/search?q=%%23%@'>%@</a>",search,matchText];
processedString = [processedString stringByReplacingOccurrencesOfString:matchText
withString:searchHTML];
NSLog(@"match: %@", processedString);
}
将无法正常工作。尝试纠正问题,如果您无法解决问题,请在此处查看解决方案:http://pastebin.com/DyQqtRzA
编辑:在此处添加解决方案:
{{1}}