过程中的动态更新查询

时间:2013-05-22 04:28:50

标签: sql oracle plsql

我正在尝试为DB中所有表中列出的列创建动态UPDATE查询。但是,查询失败并显示错误代码:-942消息:ORA-00942:表或视图不存在ORA-06512:位于“MANTAS.P_JRSDCN_TR”,第14行。

代码: -

CREATE or REPLACE PROCEDURE P_JRSDCN_TR
(
out_error_cd out number,        -- Returns 0 if no error; anything else is an error
out_error_msg out varchar2       -- Returns empty string if no error; otherwise the error and trace
)AUTHID CURRENT_USER
IS
    counter  number(20) :=0;   
CURSOR TAB_COL_CURSOR IS 
SELECT DISTINCT OWNER||'.'||TABLE_NAME as TABLE_NAME,COLUMN_NAME FROM ALL_TAB_COLS WHERE TABLE_NAME IN ('KDD_REVIEW') AND COLUMN_NAME='JRSDCN_CD';
 BEGIN  
     FOR TAB_COL_REC  IN TAB_COL_CURSOR
     LOOP

EXECUTE IMMEDIATE 'UPDATE TAB_COL_REC.TABLE_NAME SET TAB_COL_REC.COLUMN_NAME = P2||SUBSTR(TAB_COL_REC.COLUMN_NAME,3) WHERE SUBSTR(TAB_COL_REC.COLUMN_NAME,1,2)= PL';

counter := counter +SQL%rowcount ;
 If counter >= 50000 then
     counter := 0;
     --commit;
    end if;

-- Done!    
    out_error_cd := 0;
    out_error_msg := '';
    dbms_output.put_line('Turkey Jurisdiction Update completed sucessfully at ' || to_char(sysdate,'MM/dd/yyyy HH24:MI:SS'));
        END Loop;
exception when others then
        rollback;
        out_error_cd := SQLCODE;
        out_error_msg := substr(sqlerrm, 1, 200) || chr(10) || substr(DBMS_UTILITY.FORMAT_ERROR_BACKTRACE, 1, 3896);        
        dbms_output.put_line('  Code: ' || out_error_cd);
        dbms_output.put_line('  Message: ' || out_error_msg);
        dbms_output.put_line('Turkey Jurisdiction Update FAILED at ' || to_char(sysdate,'MM/dd/yyyy HH24:MI:SS'));
 end;
 /

感谢您对此程序的帮助。

3 个答案:

答案 0 :(得分:1)

可能没有名为TAB_COL_REC.TABLE_NAME

的表格

你可能想要这样的东西:

EXECUTE IMMEDIATE 'UPDATE ' || TAB_COL_REC.TABLE_NAME || ' SET ' || TAB_COL_REC.COLUMN_NAME || ' = P2||SUBSTR(' || TAB_COL_REC.COLUMN_NAME ||',3) WHERE SUBSTR(' || TAB_COL_REC.COLUMN_NAME || ',1,2)= PL';

答案 1 :(得分:0)

答案 2 :(得分:0)

http://vijvipin.wordpress.com/2009/02/18/plsql-finding-a-column-name-in-all-表格/

从all_tab_columns中选择a.table_name,column_name,DATA_TYPE,DATA_LENGTH a,USER_ALL_TABLES你  其中a.TABLE_NAME = u.TABLE_NAME  和column_name之类的'empid%'  按DATA_LENGTH desc排序;