Question

http://www.learnpython.org/page/Exception%20Handling

我无法修复代码以使用try/except

显示答案

给定代码：

#Handle all the exceptions!
#Setup
actor = {"name": "John Cleese", "rank": "awesome"}

#Function to modify, should return the last name of the actor<br>
def get_last_name():
   return actor["last_name"]

#Test code
get_last_name()
print "All exceptions caught! Good job!"<br>
print "The actor's last name is %s" % get_last_name()

然而，我能够使用以下代码获得正确的显示，但它不使用try/except

#Handle all the exceptions!
#Setup
actor = {"name": "John Cleese", "rank": "awesome"}
x = actor.pop("name")
#Function to modify, should return the last name of the actor<br><br>
def get_last_name():
   name = x.split(" ")
   last_name = name[1] #zero-based index
   return last_name

#Test code
get_last_name()
print "All exceptions caught! Good job!"
print "The actor's last name is %s" % get_last_name()

Answer 1

last_name字典中没有actor个密钥，因此当您在最后一行调用get_last_name()时，会抛出KeyError个异常。

def get_last_name():
   try:
      return actor["last_name"]
   except(KeyError):
      ## Handle the exception somehow
      return "Cleese"

显然，不是硬编码"Cleese"字符串，您可以使用上面编写的逻辑来拆分“名称”字段并从中获取姓氏。

LearnPython.org教程（异常处理）

1 个答案: