Powershell - 你如何解析内容:从RSS feed(XML)编码?

时间:2013-05-21 18:37:18

标签: xml powershell rss

我正在尝试使用PowerShell解析RSS提要中的数据。

如何获取,标题,指南和内容的内容:编码字段?

出于某种原因,我的代码只返回“...”。

任何帮助都非常感谢!

[xml]$hsg = Invoke-WebRequest http://technet.microsoft.com/en-us/security/rss/comprehensive
#$hsg.rss.channel.item | select title #this prints the list of blog posts

$ContentNamespace = New-Object Xml.XmlNamespaceManager $hsg.NameTable 
$ContentNamespace.AddNamespace("content", "http://purl.org/rss/1.0/modules/content/")

#$hsg.rss.channel.item #this prints the list of posts

$hsg.rss.channel.item.selectSingleNode("content:encoded", $ContentNamespace)

数据如下:

<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rssdatehelper="urn:rssdatehelper" version="2.0">
<channel>
<title>Microsoft Security Content: Comprehensive Edition</title>
<link>http://technet.microsoft.com/security/bulletin</link>
<dc:date>Wed, 15 May 2013 08:00:00 GMT</dc:date>
<generator>umbraco</generator>
<description>Microsoft Security Content: Comprehensive Edition</description>
<language>en-US</language>
<item>
<title>
MS13-045 - Important : Vulnerability in Windows Essentials Could Allow Information Disclosure (2813707) - Version: 1.1
</title>
<link>
http://technet.microsoft.com/en-us/security/bulletin/ms13-045
</link>
<dc:date>2013-05-15T07:00:00.0000000Z</dc:date>
<guid>
http://technet.microsoft.com/en-us/security/bulletin/ms13-045
</guid>
<content:encoded>
<![CDATA[
Severity Rating: Important<br />
 Revision Note: V1.1 (May 15, 2013): Corrected link to the download location in the Detection and Deployment Tools and Guidance section. This is an informational change only.<br />
 Summary: This security update resolves a privately reported vulnerability in Windows Writer. The vulnerability could allow information disclosure if a user opens Writer using a specially crafted URL. An attacker who successfully exploited the vulnerability could override Windows Writer proxy settings and overwrite files accessible to the user on the target system. In a web-based attack scenario, a website could contain a specially crafted link that is used to exploit this vulnerability. An attacker would have to convince users to visit the website and open the specially crafted link.
]]>
</content:encoded>
</item>

谢谢!

2 个答案:

答案 0 :(得分:3)

试试这个:

$rss = [xml](Get-Content .\test.rss)
$rss.SelectNodes('//item') | % {
    $posts += New-Object psobject -Property @{
        Title = $_.Title.Trim()
        Guid = $_.Guid.Trim()
        Content = $_.Encoded."#cdata-section".Trim()
    }
}

解析数据的示例(该数组只包含一个项目,因为样本中只有一个项目):

$posts

Title                             Guid                             Content                         
-----                             ----                             -------                         
MS13-045 - Important : Vulnera... http://technet.microsoft.com/... Severity Rating: Important<br...
顺便说一句,您的样本最终缺少以下内容:

</channel>
</rss>

答案 1 :(得分:0)

您可以绕过将输出写入中间文件,跳过 get-content 。 Frode将它很好地打包到一个提供解决方案的psobject中。

cls
$x=[xml](iwr 'https://technet.microsoft.com/en-us/security/rss/comprehensive').content
foreach ($y in $x.rss.channel.selectnodes('//item')) {
"`r`n`t$($y.title)"

$y.pubdate
$y.link
$y.encoded.'#cdata-section'

}

你可能会发现你的rss / atom返回一个稍微不同的结构,我发现这对于另一个feed是必要的:

foreach ($y in $x.feed.entry)

IDE中的intellisense帮助我进行导航。