Question

我在尝试使用BouncyCastle加密和解密字符串时遇到问题。

我正在关注http://www.aviransplace.com/2004/10/12/using-rsa-encryption-with-java/的示例，我的代码如下：

public class Cryptotests {

    public static final String ALGORITHM = "RSA";

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {

        try {
            init();
            KeyPair kp = generateKey();
            byte[] enc = encrypt("The Fat Cat Jumped Over the Bat".getBytes("UTF8"), kp.getPublic());
            byte[] dec = decrypt(enc, kp.getPrivate());
        } catch (Exception ex) {
            Logger.getLogger(Cryptotests.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

    public static void init() {
        Security.addProvider(new BouncyCastleProvider());
    }

    public static KeyPair generateKey() throws NoSuchAlgorithmException {
        KeyPairGenerator keyGen = KeyPairGenerator.getInstance(ALGORITHM);
        keyGen.initialize(1024);
        KeyPair key = keyGen.generateKeyPair();
        return key;
    }

    /**
     * Encrypt a text using public key.
     *
     * @param text The original unencrypted text
     * @param key The public key
     * @return Encrypted text
     * @throws java.lang.Exception
     */
    public static byte[] encrypt(byte[] text, PublicKey key) throws Exception {

        byte[] cipherText = null;
        // get an RSA cipher object and print the provider
        Cipher cipher = Cipher.getInstance(
                "RSA / ECB / PKCS1Padding");
        System.out.println(
                "nProvider is:" + cipher.getProvider().getInfo());

        // encrypt the plaintext using the public key
        cipher.init(Cipher.ENCRYPT_MODE, key);
        cipherText = cipher.doFinal(text);
        return cipherText;

    }

    /**
     * Decrypt text using private key
     *
     * @param text The encrypted text
     * @param key The private key
     * @return The unencrypted text
     * @throws java.lang.Exception
     */
    public static byte[] decrypt(byte[] text, PrivateKey key) throws Exception {

        byte[] dectyptedText = null;
        // decrypt the text using the private key
        Cipher cipher = Cipher.getInstance("RSA/ECB/PKCS1Padding");
        cipher.init(Cipher.DECRYPT_MODE, key);
        dectyptedText = cipher.doFinal(text);
        return dectyptedText;
    }
}

当我运行此代码时，我最终得到一个错误：

May 21, 2013 10:20:31 AM cryptotests.Cryptotests main
SEVERE: null
java.security.InvalidKeyException: Illegal key size or default parameters
    at javax.crypto.Cipher.checkCryptoPerm(Cipher.java:1011)
    at javax.crypto.Cipher.init(Cipher.java:1209)
    at javax.crypto.Cipher.init(Cipher.java:1153)
    at cryptotests.Cryptotests.encrypt(Cryptotests.java:70)
    at cryptotests.Cryptotests.main(Cryptotests.java:34)

我真的很新，老实说，在加密方面感觉有点迷失。我的目标是弄清楚这一点，以便我可以使用SHA512和4k长度创建和使用RSA密钥对。我很难找到如何实现这一目标的明确例子。

Answer 1

需要安装Unlimited Java Cryptography Extension（JCE）Unlimited Strength

http://www.oracle.com/technetwork/java/javase/downloads/jce-7-download-432124.html

使用BouncyCastle加密String的问题

1 个答案: