您好我刚刚完成了一个代码,其中我得到了50个变量......所有这些变量都带有int值..
我将变量作为separete值,只是对于这个例子,我将使用结果设置变量,但结果来自其他评估和其他东西很好,导致我已经回复了验证结果。
$one = 13
$two = 35
$three = 46
The "item1" appears <?PHP echo $one; ?> times<br />
The "item2" appears <?PHP echo $two; ?> times<br />
The "item3" appears <?PHP echo $three; ?> times<br />
这很好,但是,我如何以ASC方式或DSC订购结果,以便通过......建立订单?
非常感谢
到目前为止,这是非常好的
$naturales = array(
$uno => "n1",
$dos => "n2",
$tres => "n3",
$cuatro => "n4",
$cinco => "n5",
$seis => "n6",
$siete => "n7",
$ocho => "n8",
$nueve => "n9",
$diez => "n10",
$once => "n11",
$doce => "n12",
$trece => "n13",
$catorce => "n14",
$quince => "n15",
$dieciseis => "n16",
$diecisiete => "n17",
$dieciocho => "n18",
$diecinueve => "n19",
$veinte => "n20",
$veintiuno => "n21",
$veintidos => "n22",
$veintitres => "n23",
$veinticuatro => "n24",
$veinticinco => "n25",
$veintiseis => "n26",
$veintisiete => "n27",
$veintiocho => "n28",
$veintinueve => "n29",
$treinta => "n30",
$treintayuno => "n31",
$treintaydos => "n32",
$treintaytres => "n33",
$treintaycuatro => "n34",
$treintaycinco => "n35",
$treintayseis => "n36",
$treintaysiete => "n37",
$treintayocho => "n38",
$treintaynueve => "n39",
$cuarenta => "n40",
$cuarentayuno => "n41",
$cuarentaydos => "n42",
$cuarentaytres => "n43",
$cuarentaycuatro => "n44",
$cuarentaycinco => "n45",
$cuarentayseis => "n46",
$cuarentaysiete => "n47",
$cuarentayocho => "n48",
$cuarentaynueve => "n49",
$cincuenta => "n50",
$cincuentayuno => "n51",
$cincuentaydos => "n52",
$cincuentaytres => "n53",
$cincuentaycuatro => "n54",
$cincuentaycinco => "n55",
$cincuentayseis => "n56",
);
krsort($naturales);
foreach ($naturales as $count => $name) {
echo "The \"$name\" appears $count times<br />";
}
为什么我的结果是这样的(它隐藏所有结果12(类似计数结果) 例如,对于&#34; n3&#34;出现了12次。而且没有列出。
The "n20" appears 12 times
The "n30" appears 11 times
The "n37" appears 10 times
The "n41" appears 9 times
The "n42" appears 8 times
The "n45" appears 7 times
The "n47" appears 6 times
The "n35" appears 5 times
The "n44" appears 4 times
The "n46" appears 2 times
The "n56" appears 0 times
答案 0 :(得分:3)
构建数组
$myresults = array("Item1"=>13,"item2"=>35,"item3"=>46);
然后在数组$ myresults
上使用asort()
或arsort()
然后执行for / foreach循环以输出结果
基本指南但是你应该能够谷歌如何相当容易地详细实施(即使在这里也会有效)
答案 1 :(得分:1)
如上所述,您可以将值插入关联数组,即:
$items = array(
$one => "item1",
$two => "item2",
$three => "item3"
);
然后您可以使用像ksort()这样的函数来对所有值进行排序: http://php.net/manual/en/function.ksort.php
所以你最终会得到这样的东西:
ksort($items);
foreach ($items as $count => $name) {
echo "The \"$name\" appears $count times<br />";
}
答案 2 :(得分:1)
$one = 13;
$two = 35;
$three = 46;
$arr = array("Item 1"=>$one,"Item 2"=>$two,"Item 3"=>$three);
echo "<strong>Original</strong><br />";
foreach($arr as $k => $v){
echo $k . " = " . $v . "<br />";
}
asort($arr);
echo "<strong>Ascending Sort</strong><br />";
foreach($arr as $k => $v){
echo $k . " = " . $v . "<br />";
}
arsort($arr);
echo "<strong>Descending Sort</strong><br />";
foreach($arr as $k => $v){
echo $k . " = " . $v . "<br />";
}
如前所述,您可以根据需要使用asort
和arsort
对数组进行排序...我在这里添加了一些示例以及一些正在运行的 CODE 强>