我正在使用带有django 1.1的appengine补丁(带有appengine补丁)。 我有一个包含多列和多个文件的页面。 在管理员中,我希望能够上传图像并在列中写入文本,如下所示:
This is the sory of bugs bunny ...
<img src="/pages/file/agphZXAtc2FtcGxlchALEgpwYWdlc19maWxlGAUM/" alt="didnt work" />
some more text about bugs bunny ...
(其中get_absolute_url显示我/ pages / file / agphZXAtc2FtcGxlchALEgpwYWdlc19maWxlGAUM /)
我的麻烦是要在页面上渲染图像,上面显示“没有工作”而不是渲染图像。 我可以去页面,列和文件的详细页面。 我没有正确完成模型,app.yaml是否需要一些东西,我不应该为文件的通用URL传递模板吗?
urlpatterns += patterns('',
url(r'^index/$', direct_to_template,
{'template': 'base.html'}, name="main-view"),
url(r'^pages/page/(?P<object_id>.+)/$', object_detail,
{'queryset': Page.all(),
'template_name': 'pages_page_detail.html'}, name="pages_page_detail_view"),
url(r'^pages/column/(?P<object_id>.+)/$', object_detail,
{'queryset': Column.all(),
'template_name': 'pages_column_detail.html'}, name="pages_column_detail_view"),
url(r'^pages/file/(?P<object_id>.+)/$', object_detail,
{'queryset': File.all(),
'template_name': 'pages_file_detail.html'}, name="pages_file_detail_view"),
url(r'^pages/$', object_list,
{'queryset': Page.all(), 'paginate_by': 3, 'template_name': 'pages_page_index.html'}, name="page_index_view"),
)
class Page(db.Model):
"""Page model."""
title = db.StringProperty(_('title'), required=True)
author = db.ReferenceProperty(User)
status = db.StringProperty(_('status'), choices=[_('draft'),
_('public'),
_('hidden'),
])
created = db.DateTimeProperty(_('created'))
modified = db.DateTimeProperty(_('modified'))
non_indexable = db.BooleanProperty(_('hide from index'))
def __unicode__(self):
return '%s' % self.title
@permalink
def get_absolute_url(self):
return ('pages_page_detail_view', [self.key()])
class File(db.Model):
"""File model."""
title = db.StringProperty(_('title'))
data = db.BlobProperty()
added = db.DateTimeProperty(_('added'))
page = db.ReferenceProperty(Page)
#content_type = FakeModelProperty(ContentType, required=True)
def __unicode__(self):
return '%s' % self.get_absolute_url()
@permalink
def get_absolute_url(self):
return ('pages_file_detail_view', [self.key()])
class Column(db.Model):
"""Column model."""
title = db.StringProperty(_('title'))
data = db.TextProperty(_('data'))
page = db.ReferenceProperty(Page)
def __unicode__(self):
return '%s' % self.title
@permalink
def get_absolute_url(self):
return ('pages_column_detail_view', [self.key()])
application: aep-sample
version: 1
runtime: python
api_version: 1
default_expiration: '3650d'
handlers:
- url: /remote_api
script: $PYTHON_LIB/google/appengine/ext/remote_api/handler.py
secure: optional
login: admin
- url: /media
static_dir: _generated_media
secure: optional
- url: /.*
script: common/appenginepatch/main.py
secure: optional
答案 0 :(得分:1)
“/ pages / file / agphZXAtc2FtcGxlchALEgpwYWdlc19maWxlGAUM /”应返回图像。据我现在你可以告诉你的urls.py你现在返回html(必须看模板才能确定)
这是一个可以使用正确的mimetype
返回JPEG图像的视图def get_image(request, object_id):
file = get_object_or_404(File, pk=object_id)
return HttpResponse(file.data, mimetype='image/jpeg')
然后将urls.py更改为
url(r'^pages/file/(?P<object_id>.+)/$', get_image)
答案 1 :(得分:1)
我做了以下更改:
url(r'^pages/file/(?P<object_id>.+)/$', 'pages.views.download_file',
name="pages_file_download_view"),
def download_file(request, object_id):
file = get_object_or_404(File, object_id)
return HttpResponse(file.data,
content_type=guess_type(file.title)[0] or 'application/octet-stream')
@permalink
def get_absolute_url(self):
return ('pages_file_download_view', [self.key()])
谢谢!