Question

以下是我配置的配置文件

WEB-INF / classes / applicationContext.xml但它正在搜索 WEB-INF / applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="starter_anil" version="2.4" 
         xmlns="http://java.sun.com/xml/ns/j2ee" 
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
         xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Anil-Spring</display-name>
    <!-- Servlets -->
    <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>WEB-INF/classes/applicationContext.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

    <!-- Listeners -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
</web-app>

我正在接受例外

EVERE: Context initialization failed
org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from ServletContext resource [/WEB-INF/applicationContext.xml]; nested exception is java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/applicationContext.xml]

这是我的applicationContext

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">

<beans>
    <import resource="config/controllers.xml" />
    <!-- <import resource="conf/spring/services.xml" />
    <import resource="conf/spring/persistence.xml" />
    <import resource="conf/spring/daos.xml" />
    <import resource="conf/spring//interceptors.xml" /> -->
</beans>

解决方法是

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="starter_anil" version="2.4" 
         xmlns="http://java.sun.com/xml/ns/j2ee" 
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
         xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Anil-Spring</display-name>
    <!-- Servlets -->
    <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/classes/applicationContext.xml</param-value>
        </init-param> 
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/classes/applicationContext.xml</param-value>
    </context-param>

    <!-- Listeners -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
</web-app>

警告：找不到带URI的HTTP请求的映射 DispatcherServlet中的[/AnilsSpring/WEB-INF/jsp/hello.jsp]名称 'MVC-调度' 请指导我一次

Answer 1

为什么你的applicationContext在课堂上？将其移至WEB-INF目录，如评论中所述。这应该解决问题。

/ classes目录用于编译的类，但不用于配置文件。

Answer 2

尝试在/

中添加/WEB-INF/classes/applicationContext.xml

如果它仍然不起作用，请尝试在web.xml（在servlet声明之前）中添加它

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        /WEB-INF/classes/applicationContext.xml
    </param-value>
</context-param>

Answer 3

<?xml version="1.0" encoding="UTF-8"?>

<web-app id="starter_anil" version="2.4" 
         xmlns="http://java.sun.com/xml/ns/j2ee" 
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
         xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Anil-Spring</display-name>
        <!-- Servlets -->
   <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/classes/applicationContext.xml</param-value>
       </init-param> 
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/classes/applicationContext.xml</param-value>
    </context-param>



    <!-- Listeners -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>





</web-app>

这使得tomcat上的异常开始少，但我有点困惑

Answer 4

如果您绝对必须拥有它，请尝试：

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="starter_anil" version="2.4" 
    xmlns="http://java.sun.com/xml/ns/j2ee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Anil-Spring</display-name>
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:applicationContext.xml</param-value> 
    </context-param>

    <the-rest-of-your-stuff />
</web-app>

/之前可能需要applicationContext.xml，但我不这么认为。

Answer 5

可能是你需要取消部署。并部署它。它会工作。。它适用于我的例外 IOException从ServletContext资源解析XML文档[/ WEB-INF / classes / spring application config.xml];

Answer 6

WEB-INF / classes / applicationContext.xml对于这个要求，你必须把applicationContext.xml放在类路径中，即

如果您使用的是maven，请将其放在src / main / resources文件夹中，否则放入src文件夹。

然后你会在WEB-INF / classes

中找到它

没有使用Configured name查找Spring配置

6 个答案: