Question

 <h:panelGroup id="userPanel"><f:subview rendered="#{searchView.isUser}">
    <h:commandButton value="test" action="#{searchAction.doFindUsers}"   >
        <f:ajax execute="@this" event="action" render="userPanel" />
    </h:commandButton> </f:subview></h:panelGroup>

我收到的错误是：无法在组件j_idt26

的上下文中找到它

Answer 1

因为<f:subview>是NamingContainer。

另见：

How to find out client ID of component for ajax update/render? Cannot find component with expression "foo" referenced from "bar"

只需使用<h:panelGroup>，

<h:panelGroup id="userPanel">
    <h:panelGroup rendered="#{searchView.isUser}">
        <h:commandButton value="test" action="#{searchAction.doFindUsers}">
            <f:ajax execute="@this" event="action" render="userPanel" />
        </h:commandButton>
    </h:panelGroup>
</h:panelGroup>

或<ui:fragment>（只有少量开销）

<h:panelGroup id="userPanel">
    <ui:fragment rendered="#{searchView.isUser}">
        <h:commandButton value="test" action="#{searchAction.doFindUsers}">
            <f:ajax execute="@this" event="action" render="userPanel" />
        </h:commandButton>
    </ui:fragment>
</h:panelGroup>

或者在这个具体的例子中直接在命令按钮上（当然你的情况比这更复杂）

<h:panelGroup id="userPanel">
    <h:commandButton value="test" action="#{searchAction.doFindUsers}"  rendered="#{searchView.isUser}">
        <f:ajax execute="@this" event="action" render="userPanel" />
    </h:commandButton>
</h:panelGroup>

当我通过<f：subview>标签访问时，为什么找不到<h：panelgroup> id？</f：subview> </h：panelgroup>

1 个答案:

另见：

另见：