Question

我写了一些javascript来验证字符串是字母数字，但我只是想知道如何添加一些代码来包含连字符（ - ）和斜杠（/）作为可接受的输入。这是我目前的代码：

function validateAddress() {
  var address = document.getElementById('address');

  if (address.value == "") {
    alert("Address must be filled out");
    return false;
  } else if (document.getElementById('address').value.length > 150) {
    alert("Address cannot be more than 150 characters");
    return false;
  } else if (/[^a-zA-Z0-9\-\/]/.test(address)) {
    alert('Address can only contain alphanumeric characters, hyphens(-) and back slashs(\)');
    return false;
  }
}

Answer 1

只需将它们添加到角色组即可。当然，因为-和/在此上下文中都是特殊字符（/结束了一个RegExp，-表示一个范围），所以你需要逃脱他们前面有\：

function validateAddress(){
    var TCode = document.getElementById('address').value;

    if( /[^a-zA-Z0-9\-\/]/.test( TCode ) ) {
        alert('Input is not alphanumeric');
        return false;
    }

    return true;     
}

Answer 2

function isValidCharacter(txtTitle) {   
     var title = document.getElementById(txtTitle);
     var regExp = /^[a-zA-Z]*$/
     if (!regExp.test(title.value)) {
        title.value = '';
        return false;
        }
      else {      
           return true;
        }
   }


function Validation(){
 var txtTitles = document.getElementById('txtTitle');
  if (isValidCharacter(txtTitles.id) == false) {
   alert("Please enter valid title. No special character allowed.");        
    return false;
  }  
 }



   $("#Btn").unbind("click").click(function () {
        if (Validation() == false) {

        }
        else {
              //success     
        }
   }

Answer 3

function namefun(c)
            {   
                var spch=/[A-z\s]/ig;
                var dig=/[0-9]/g;
                var ln=c.length;
                var j=1;
                for(var i=0;i<ln;i++)
                {
                    var k=c.slice(i,j);
                    if((spch.test(c)==false)||(dig.test(c)==true))
                    {
                        alert("Invalid name");
                        document.getElementById('tname').value="";
                        ln=0;
                        setTimeout(function(){tname.focus();}, 1);
                        //return false;
                    }
                    j++;
                }

            }

Answer 4

简单的 Javascript 版本

isValidCharacter(text) {
  const validCharacterRegex = /^[a-zA-Z]*$/;
  return validCharacterRegex.test(text);
}

打字稿版本

isValidCharacter(text: string): boolean {
  const validCharacterRegex: RegExp = /^[a-zA-Z]*$/;
  return validCharacterRegex.test(text);
}

特殊字符验证

4 个答案: