Question

我有一个方法，我从android中使用http post从webservice获取数据。

我的代码是，

public class PropertyRequestService  {

static String result;
PropertiesList localProperty = new PropertiesList();
List<PropertiesList> Properties;
List<PropertiesList> PropertiesRS;

public List<PropertiesList>  getAllPropertiesStuff() {

    try {

        HttpClient client = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(
                "Here Given Webservice URL");
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs
                .add(new BasicNameValuePair("string", "value"));

        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = client.execute(httppost);

        HttpEntity entity = response.getEntity();
        if (entity != null) {


            InputStream instream = entity.getContent();
           String response1= convertStreamToString(instream);

            // Closing the input stream will trigger connection release
            instream.close();
            //result = EntityUtils.toString(entity);
            Log.i("RESPONSE=", response1);

            JSONObject json = new JSONObject(response1);

            PropertiesRS.add(SplitResult(json));
        }
    } catch (Exception e1) {
        e1.printStackTrace();
    }

    return PropertiesRS;
}

 public static String convertStreamToString(InputStream instream) {

     BufferedReader reader = new BufferedReader(new InputStreamReader(instream));
        StringBuilder sb = new StringBuilder();

        String line = null;
        try {
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                instream.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return sb.toString();
}

这是logcat，

05-21 11:44:27.320: W/System.err(13234): org.json.JSONException: Value <?xml of type java.lang.String cannot be converted to JSONObject
05-21 11:44:27.320: W/System.err(13234):    at org.json.JSON.typeMismatch(JSON.java:107)
05-21 11:44:27.320: W/System.err(13234):    at org.json.JSONObject.<init>(JSONObject.java:158)
05-21 11:44:27.328: W/System.err(13234):    at org.json.JSONObject.<init>(JSONObject.java:171)
05-21 11:44:27.328: W/System.err(13234):    at com.BuildersUpdate.PropertySearchTypes.PropertyRequestService.getAllPropertiesStuff(PropertyRequestService.java:68)

我的webservice以这种格式返回数据

05-21 11:44:27.320: I/RESPONSE=(13234): <?xml version="1.0" encoding="utf-8"?>
05-21 11:44:27.320: I/RESPONSE=(13234): <string xmlns="http://localhost/">[{"TbbId":0,"PropertyID":1066666,"BuilderID":"9250c666-e76c-4206-8b37-343b2bb11a89","BuilderName":"David Weekley Homes","Notes":"","Address":"1 TBB4307","SchoolDistrict":null,"School":null,"CityID":"Austin","CountyID":"","StateID":"TX","Zip":"78737","Lat":"30.192781000000000","Lng":"-97.984480000000000","Price":391990,"PropertyStatusID":"AV","PropertyStatusDescription":"Available","StageID":"TBB","StageDescription":"To-Be-Built Home","TypeID":1,"TypeDescription":"House","SubdivisionID":3312,"SubdivisionName":"Belterra","FloorPlanNumber":"4307","Remarks":"","OldNew":null,"PropertyInMyListFlag":null,"FreePostingFlag":"F","PropertySubscriptionPlan":null,"PropertySubscriptionPaymentType":null,"BalanceAmount":0,"PropertyLicenseFlag":"N","PlanNumber":null,"SubdivisionFloorPlanID":null,"SubdivisionFloorPlanName":"Newtown","ShowDirections":"Monday-Saturday 10am-6pm\nSunday 12pm-6pm ","DrivingDirections":"From HWY 290, Take 290 West towards Dripping Springs. Belterra is 7 miles past the intersection of 290 and 71 on the left. Turn left onto Belterra Drive. Turn right onto Abbott Drive, our model is on the left.","PropertyClass":"TBB","RemarksId":0,"VerifiedBU":"Y","SubdivisionDescription":null,"Contact1Name":"Rachea McMurray-Pendley","Contact1Phone":"866-933-5539","Contact1PhoneAlt":"","Contact2Name":"Telenna Thompson","Contact2Phone":"512-821-8821","Contact2PhoneAlt":"","Email":"","Beds":4,"Baths":3,"HalfBaths":1,"Living":0,"Dining":0,"OtherRooms":"","Stories":2.0,"Master":"Down","Garage":3.0,"SquareFeet":3320,"LotSize":"","LotDescription":"Enjoy a host of amenities and award-winning homes in Belterra, a premier community in Austin, Texas. Located just minutes from downtown Austin, Belterra offers residents the opportunity to live, work and play in a community that fits their lifestyle. Here, you can enjoy the &amp;ldquo;Exemplary&amp;rdquo; schools of Dripping Springs ISD plus: &amp;nbsp; Resort-style pool with splash pad for the kids Rooster Springs Elementary School on site Recreation center, outdoor pavilion, club house and fitness center Sport court, ball fields and several children's playscapes Over 400 acres dedicated to parks, sports fields and undisturbed green spaces Miles of walking trails to enjoy the great outdoors 70 x 130 homesites that back up to greenbelts with gorgeous hill country views Over 400 acres dedicated to parks, sports fields and undisturbed green space","CommunityTypeID":11,"CommunityTypeDescription":"Standard","LotWidth":0,"LotLength":0,"Acres":0,"Water":"","Sewer":"","DryUtilities":"","Topography":"","Trees":"","VirtualTourURL":"","InternetOption":"","WaterId":0,"SewerId":0,"DryUtilitiesId":0,"TopographyId":0,"TreesId":0,"InternetOptionId":0,"WaterIds":null,"SewerIds":null,"DryUtilitiesIds":null,"TopographyIds":null,"TreesIds":null,"InternetOptionIds":null,"MinimumPrice":0,"MaximumPrice":0,"MinimumPropertySquareFeet":0,"MaximumPropertySquareFeet":0,"MinimumBeds":0,"MaximumBeds":0,"MinimumBaths":0,"MaximumBaths":0,"MinimumHalfBaths":0,"MaximumHalfBaths":0,"MinimumStories":0,"MaximumStories":0,"MinimumGarages":0,"MaximumGarages":0,"IsModel":null,"CustomHomeModelId":0,"BrandName":null,"SchoolDistrictID":0,"SchoolDistrictName":null,"ElementarySchool":null,"MiddleSchool":null,"HighSchool":null,"SchoolComments":"Please visit the school district's website for additional information about attendance boundaries and school activities.","HasHOA":true,"HOA":"","HOAFee":106.25,"HOABillingPeriod":"Quarterly","CommissionPaid":"TBD","BuyerIncentive":"Please call for current incentives.","AgentIncentive":"Please call for current incentives.","PropertyImageID":5775047,"PropertyImage":"PropertyImages/20130316\\P1066666__031613163405_2040133366_5775047.jpg","IsModified":false,"StatusID":40,"StatusDescription":"Active","EntryDate":new Date(1350438245980),"ModifyDate":new Date(1363450564963),"AvailableDate":new Date(-59011459200000),"UserIDModifiedBy":"4a2aef16-e7d9-469a-95ad-5c8935cb6bab","UserIDApprovedBy":"0000000

我不知道为什么要提出这个例外。

由于客户端要求的限制，我无法将应用程序更改为以json格式发送数据。

如何将响应转换为android中的json对象？这正在吞噬我宝贵的时间而不是继续前进。我被困在这里。

请提出任何想法或建议！

提前致谢..

Answer 1

当您获得XML标记所涵盖的JSON响应时，您必须编写一个逻辑来为您提供JSON数据。

/**
 * To fetch JSON Text between XML tags
 * For example: 
 * <string xmlns="http://schemas.microsoft.com/2003/10/Serialization/"> JSON Response text </string>
 * @param response
 * @return
 */
public String getJSONString(HttpResponse response) {

    try {
         DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
         Document doc = builder.parse(response.getEntity().getContent());
         NodeList nl = doc.getElementsByTagName("string");
         Node n = nl.item(0);
         String str = n.getFirstChild().getNodeValue();
         System.out.println("Node value : " + str);
         return str;
    } catch (ParserConfigurationException e) {
         e.printStackTrace();
    } catch (SAXException e) {
         e.printStackTrace();
    } catch (IllegalStateException e) {
         // TODO Auto-generated catch block
         e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
 return null;
}

org.json.JSONException：值<！ - ？类型java.lang.String的xml无法转换为JSONObject - >

1 个答案: