Question

我正在寻找一个Android应用程序，它将调用我在计算机上制作的有趣小脚本。当我在网络浏览器中打开脚本时，计算机将运行“beep”命令。我如何从Android应用程序内部执行此操作，以便当我按下按钮时它会调用网站并发出嘟嘟声我的计算机？我试过这个，但它似乎对我不起作用。

HttpGet httpget = new HttpGet(
    "http://www.blah.com/beep.php");

更多信息：我正在服务器上运行的代码：

beeping!
<?php
shell_exec("beep -f 2000 -r 3 -l 100 -d 20"); ?>

我正在运行的应用程序有一个调用beep方法的按钮。

公共类MainActivity扩展了Activity {

@Override
  protected void onCreate(Bundle savedInstanceState) {
   super.onCreate(savedInstanceState);
   setContentView(R.layout.activity_main);
 }

@Override
 public boolean onCreateOptionsMenu(Menu menu) {
 // Inflate the menu; this adds items to the action bar if it is present.
 getMenuInflater().inflate(R.menu.main, menu);
 return true;
} //here is the error that says i need to remove this token

new Thread(new Runnable() {
  public void run(){
    try{
      HttpClient httpclient = new DefaultHttpClient();

      HttpGet httpget = new HttpGet(
        "http://www.blah.com/beep.php");
    }
    catch(Exception e){
      throw e;
  }}
}).start();
} //here is the error to insert } to complete classbody

Answer 1

new Thread(new Runnable() {
public void run() {
    try {
    HttpClient httpclient = new DefaultHttpClient();

    HttpGet httpget = new HttpGet(
        "http://www.blah.com/beep.php");
    HttpResponse response = httpclient.execute(httpget);
    } catch(Exception x) {
        ...
    }}
}).start();

用于访问网站的Android应用代码

1 个答案: