转换为导出String

Question

嘿我无法弄清楚如何将类型作为String返回，因为我已将outputGrade定义为String但我正在尝试计算单个数字。例如mark = 79然后输出字符串=“9”

private static String printResult (int numAssignments, double  studentMark)
        {
        int outputGradeSingle;
        String outputGrade;
        switch (numAssignments)
        {
        case 0:  outputGrade="DNA-";
        break;
        case 1: case 2: case 3: case 4: outputGrade="DNC-";
        break;
        case 5: if (studentMark<50.0)
                {
                outputGrade="F-";
                }
                else
                {
                outputGradeSingle=(studentMark/10);
                outputGrade= String.valueOf(outputGradeSingle);
                }
        break;
        default: outputGrade="Not a valid amount of assignments, range is between 0 and 5";
        break;
        }
        return outputGrade;
        }
}

Answer 1

这是因为您要为double分配int，并且您收到possible loss of precision错误。只是显式地转换结果int，你应该没问题（假设你可以截断小数）：

outputGradeSingle = (int) (studentMark / 10);

注意：你说明了

  

mark = 79然后输出字符串=＆＃34; 9＆＃34;

如果mark为79，outputGrade将为您的代码7。