我想从纬度和经度中找到当前的位置名称，
以下是我尝试的代码段，但我的日志在除placemark，placemark.ISOcountryCode和placemark.country
我想要placemark.locality和placemark.subLocality的值，但它显示空值。
- (void)viewWillAppear:(BOOL)animated
{
[super viewWillAppear:animated];
// this creates the CCLocationManager that will find your current location
locationManager = [[CLLocationManager alloc] init];
locationManager.delegate = self;
locationManager.desiredAccuracy = kCLLocationAccuracyNearestTenMeters;
[locationManager startUpdatingLocation];
}
// this delegate is called when the app successfully finds your current location
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder reverseGeocodeLocation:locationManager.location
completionHandler:^(NSArray *placemarks, NSError *error) {
NSLog(@"reverseGeocodeLocation:completionHandler: Completion Handler called!");
if (error){
NSLog(@"Geocode failed with error: %@", error);
return;
}
NSLog(@"placemarks=%@",[placemarks objectAtIndex:0]);
CLPlacemark *placemark = [placemarks objectAtIndex:0];
NSLog(@"placemark.ISOcountryCode =%@",placemark.ISOcountryCode);
NSLog(@"placemark.country =%@",placemark.country);
NSLog(@"placemark.postalCode =%@",placemark.postalCode);
NSLog(@"placemark.administrativeArea =%@",placemark.administrativeArea);
NSLog(@"placemark.locality =%@",placemark.locality);
NSLog(@"placemark.subLocality =%@",placemark.subLocality);
NSLog(@"placemark.subThoroughfare =%@",placemark.subThoroughfare);
}];
}
// this delegate method is called if an error occurs in locating your current location
- (void)locationManager:(CLLocationManager *)manager didFailWithError:(NSError *)error
{
NSLog(@"locationManager:%@ didFailWithError:%@", manager, error);
}
提前致谢。
编辑：
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
CLLocation *currentLocation = newLocation;
if (currentLocation != nil)
NSLog(@"longitude = %.8f\nlatitude = %.8f", currentLocation.coordinate.longitude,currentLocation.coordinate.latitude);
// stop updating location in order to save battery power
[locationManager stopUpdatingLocation];
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0)
{
CLPlacemark *placemark = [placemarks lastObject];
// strAdd -> take bydefault value nil
NSString *strAdd = nil;
if ([placemark.subThoroughfare length] != 0)
strAdd = placemark.subThoroughfare;
if ([placemark.thoroughfare length] != 0)
{
// strAdd -> store value of current location
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark thoroughfare]];
else
{
// strAdd -> store only this value,which is not null
strAdd = placemark.thoroughfare;
}
}
if ([placemark.postalCode length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark postalCode]];
else
strAdd = placemark.postalCode;
}
if ([placemark.locality length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark locality]];
else
strAdd = placemark.locality;
}
if ([placemark.administrativeArea length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark administrativeArea]];
else
strAdd = placemark.administrativeArea;
}
if ([placemark.country length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark country]];
else
strAdd = placemark.country;
}
}
}];
}
答案 0 :(得分：13)
我正在给你一些我用来解析地址的片段。我还要在必要的地方发表评论，以便为您理解代码。除此之外，如果您无法理解任何内容，请随意向片段提出任何问题。
在didUpdateToLocation方法
NSLog(@"didUpdateToLocation: %@", newLocation);
CLLocation *currentLocation = newLocation;
if (currentLocation != nil)
NSLog(@"longitude = %.8f\nlatitude = %.8f", currentLocation.coordinate.longitude,currentLocation.coordinate.latitude);
// stop updating location in order to save battery power
[locationManager stopUpdatingLocation];
// Reverse Geocoding
NSLog(@"Resolving the Address");
// “reverseGeocodeLocation” method to translate the locate data into a human-readable address.
// The reason for using "completionHandler" ----
// Instead of using delegate to provide feedback, the CLGeocoder uses “block” to deal with the response. By using block, you do not need to write a separate method. Just provide the code inline to execute after the geocoding call completes.
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0)
{
placemark = [placemarks lastObject];
// strAdd -> take bydefault value nil
NSString *strAdd = nil;
if ([placemark.subThoroughfare length] != 0)
strAdd = placemark.subThoroughfare;
if ([placemark.thoroughfare length] != 0)
{
// strAdd -> store value of current location
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark thoroughfare]];
else
{
// strAdd -> store only this value,which is not null
strAdd = placemark.thoroughfare;
}
}
if ([placemark.postalCode length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark postalCode]];
else
strAdd = placemark.postalCode;
}
if ([placemark.locality length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark locality]];
else
strAdd = placemark.locality;
}
if ([placemark.administrativeArea length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark administrativeArea]];
else
strAdd = placemark.administrativeArea;
}
if ([placemark.country length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark country]];
else
strAdd = placemark.country;
}
其中strAdd将使用地理位置返回地址..
享受编程!!
答案 1 :(得分：11)
带完成块的方法：
typedef void(^addressCompletion)(NSString *);
-(void)getAddressFromLocation:(CLLocation *)location complationBlock:(addressCompletion)completionBlock
{
__block CLPlacemark* placemark;
__block NSString *address = nil;
CLGeocoder* geocoder = [CLGeocoder new];
[geocoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error)
{
if (error == nil && [placemarks count] > 0)
{
placemark = [placemarks lastObject];
address = [NSString stringWithFormat:@"%@, %@ %@", placemark.name, placemark.postalCode, placemark.locality];
completionBlock(address);
}
}];
}
这是如何使用它：
CLLocation* eventLocation = [[CLLocation alloc] initWithLatitude:_latitude longitude:_longitude];
[self getAddressFromLocation:eventLocation complationBlock:^(NSString * address) {
if(address) {
_address = address;
}
}];
答案 2 :(得分：6)
我在 Swift 3 中实施了Niru的解决方案，如果有人需要，可以在此发帖：
let geocoder = CLGeocoder()
geocoder.reverseGeocodeLocation(self.location!) { (placemarksArray, error) in
if (placemarksArray?.count)! > 0 {
let placemark = placemarksArray?.first
let number = placemark!.subThoroughfare
let bairro = placemark!.subLocality
let street = placemark!.thoroughfare
self.addressLabel.text = "\(street!), \(number!) - \(bairro!)"
}
}
答案 3 :(得分：2)
使用google api进行反向地理标记：
网址： http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&sensor=true_or_false
来自：https://developers.google.com/maps/documentation/geocoding/
答案 4 :(得分：0)
如果您要获取的位置列在此列表中，则代码中存在错误。
http://developer.apple.com/library/ios/#technotes/tn2289/_index.html#//apple_ref/doc/uid/DTS40011305
否则CLGeoCoder没有其他国家的地址。
我遇到了同样的问题所以我用它来获取地址..给出一个非常准确的地址。
http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&sensor=true_or_false
答案 5 :(得分：0)
首先，在didUpdateToLocation中过滤位置以防止使用缓存或错误的位置进行地理编码
NSTimeInterval locationAge = -[newLocation.timestamp timeIntervalSinceNow];
if (abs(locationAge) > 5.0) return;
if (newLocation.horizontalAccuracy < 0) return;
另外，尝试将reverseGeoCoding方法从didUpdateToLocation
移开答案 6 :(得分：0)
获得latitude，longitude个地理位置值后，您可以使用CLGeocoder
这是tutorial，可能对您有所帮助。
答案 7 :(得分：0)
使用此API获取数据并传递lat和long值。
答案 8 :(得分：0)
在Swift 4.1和Xcode 9.4.1中，这是我的解决方案之一。在这里，我正在使用地理编码 API来获取完整的地址。有了这个api，我也可以获得村庄名称。
我正在使用 reverseGeocodeLocation ，但它没有得到村庄地址的详细信息或村庄名称，而只是在城市名称附近。 这是最好的解决方案之一。...
func getAddressForLatLng(latitude: String, longitude: String) { // Call this function
let url = NSURL(string: "https://maps.googleapis.com/maps/api/geocode/json?latlng=\(latitude),\(longitude)")//Here pass your latitude, longitude
print(url!)
let data = NSData(contentsOf: url! as URL)
if data != nil {
let json = try! JSONSerialization.jsonObject(with: data! as Data, options: JSONSerialization.ReadingOptions.allowFragments) as! NSDictionary
print(json)
let status = json["status"] as! String
if status == "OK" {
if let result = json["results"] as? NSArray {
if result.count > 0 {
if let addresss:NSDictionary = result[0] as? NSDictionary {
if let address = addresss["address_components"] as? NSArray {
var newaddress = ""
var number = ""
var street = ""
var city = ""
var state = ""
var zip = ""
var country = ""
if(address.count > 1) {
number = (address.object(at: 0) as! NSDictionary)["short_name"] as! String
}
if(address.count > 2) {
street = (address.object(at: 1) as! NSDictionary)["short_name"] as! String
}
if(address.count > 3) {
city = (address.object(at: 2) as! NSDictionary)["short_name"] as! String
}
if(address.count > 4) {
state = (address.object(at: 4) as! NSDictionary)["short_name"] as! String
}
if(address.count > 6) {
zip = (address.object(at: 6) as! NSDictionary)["short_name"] as! String
}
newaddress = "\(number) \(street), \(city), \(state) \(zip)"
print(newaddress)
// OR
//This is second type to fetch pincode, country, state like this type of data
for i in 0..<address.count {
print(((address.object(at: i) as! NSDictionary)["types"] as! Array)[0])
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "postal_code" {
zip = (address.object(at: i) as! NSDictionary)["short_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "country" {
country = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "administrative_area_level_1" {
state = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "administrative_area_level_2" {
district = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
}
}
}
}
}
}
}
}
像这样调用此函数
self.getAddressForLatLng(latitude: "\(self.lat!)", longitude: "\(self.lng!)")
答案 9 :(得分：0)
快捷键5
import CoreLocation
func printAddress() {
if let lat = Double(30.710489), lat != 0.0, let long = Double(76.852386), long != 0.0 {
// Create Location
let location = CLLocation(latitude: lat, longitude: long)
// Geocode Location
CLGeocoder().reverseGeocodeLocation(location) { (placemarks, error) in
// Process Response
self.processResponse(withPlacemarks: placemarks, error: error)
}
}
}
private func processResponse(withPlacemarks placemarks: [CLPlacemark]?, error: Error?) {
var address = ""
if let error = error {
address = "Unable to Reverse Geocode Location (\(error))"
} else {
if let placemarks = placemarks, let placemark = placemarks.first {
address = placemark.compactAddress ?? ""
} else {
address = "No address found"
}
}
print(address)
}
extension CLPlacemark {
var compactAddress: String? {
if let name = name {
var result = name
if let street = thoroughfare {
result += ", \(street)"
}
if let city = locality {
result += ", \(city)"
}
if let postalCode = postalCode {
result += ", \(postalCode)"
}
if let country = country {
result += ", \(country)"
}
return result
}
return nil
}
}
// 2nd Way
func updateLocation(lat:Double,long:Double) {
CLGeocoder().reverseGeocodeLocation(CLLocation(latitude: Double(lat), longitude: Double(long)), completionHandler: { (placemarks, error) -> Void in
if error != nil {
return
}
else {
var location = ""
let pm = placemarks![0]
if pm.addressDictionary!["FormattedAddressLines"] != nil {
location = "\n" + (pm.addressDictionary!["FormattedAddressLines"] as! NSArray).componentsJoined(by: ", ")
}else{
location = "\n" + "NO_ADDRESS_FOUND"
}
}
})
}
答案 10 :(得分：-1)
试试这个
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error) {
//..NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0) {
placemark = [placemarks lastObject];
lblgetaddrees.text = [NSString stringWithFormat:@"%@,%@,%@,%@,%@,%@",
placemark.subThoroughfare, placemark.thoroughfare,
placemark.postalCode, placemark.locality,
placemark.administrativeArea,
placemark.country];
} else {
//..NSLog(@"%@", error.debugDescription);
}
} ];
答案 11 :(得分：-1)
这是从位置坐标（纬度，经度）获取地址的方法。
使用此代码，您可以从LocationCoordinates获取地址信息，例如城市，国家/地区，邮政编码等。
func getReverSerGeoLocation(location : CLLocation) {
print("getting Address from Location cordinate")
CLGeocoder().reverseGeocodeLocation(location) {
placemarks , error in
if error == nil && placemarks!.count > 0 {
guard let placemark = placemarks?.last else {
return
}
print(placemark.thoroughfare)
print(placemark.subThoroughfare)
print("postalCode :-",placemark.postalCode)
print("City :-",placemark.locality)
print("subLocality :-",placemark.subLocality)
print("subAdministrativeArea :-",placemark.subAdministrativeArea)
print("Country :-",placemark.country)
}
}
}
只需通过传递纬度经度作为参数，例如下面的方法，即可调用上述方法
getReverSerGeoLocation(location: CLLocation(latitude: 21.0225, longitude: 72.5714))
希望这会有所帮助！