Question

下面是我的创建表，html文件，其中包含一个包含艺术家的下拉菜单，以及一个基于艺术家的php文件显示该艺术家的所有专辑标题。

我似乎无法让php文件工作。我可以从下拉菜单中获取值，但我不认为我可以使用该值从数据库中获取值。

连接数据库

<?php
 // connect.php
 // include file providing a function to connect to a mysql database
 // include this file on every page that needs to connect to the db.

 // usage:
 // include('connect.php');

 // declare the connection function
 function dbConnect ($name, $pw) {
// Create a mysql connection
$connection = mysql_connect("localhost", $name, $pw);
// select the correct database
mysql_select_db("usr_".$name."_1", $connection);
  }

 // Call the connect function
 // First argument is the user name
 // second argument is the password
 dbConnect('yourUserName', 'yourPassword');
 ?>

表

 create table CD (
 CDnum int not null,
 Title varchar(40),
 Artist varchar(40),
 Category varchar(20),
 Price numeric(6,2)
 ) engine = InnoDB;

 create table Customer (
 Cnum int not null,
 CName varchar(25),
 CCity varchar(25)
 ) engine = InnoDB;

  create table Buys (
 Cnum int not null,
 CDnum int not null,
 Qty int not null
  ) engine = InnoDB;

带有下拉菜单的HTML文件。

<HTML>
<HEAD>
<TITLE>
listArtist
</TITLE>
<META NAME="author" CONTENT="">
</HEAD>
<BODY>
<H1>Find Artist's Albums Page</H1>
From a dropdown list of artists, a user should be able to pick an artist and see a list of albums      (all fields in the CD table) by that artist.
<HR>
<FORM ACTION="listArtist.php" METHOD="POST"/>
Artist:
<select name="mydropdown">
<option value="Pink Floyd">Pink Floyd</option>
<option value="Pearl Jam">Pearl Jam</option>
<option value="Shania Twain">Shania Twain</option>
<option value="Gwen Stefani">Gwen Stefani</option>
<option value="Vince Gill">Vince Gill</option>
<option value="Dixie Chicks">Dixie Chicks</option>
</select>
<BR>
<BR>
<INPUT TYPE="SUBMIT" Value="List Artist"/>
</FORM>
</BODY>
</HTML>

PHP文件，假设从用户那里获取艺术家并显示所有专辑的标题。

 <HTML>
 <HEAD>
 <title>listArtist.php</title>
 </HEAD>
 <BODY>
  <H1>PrintSchedule FORM ACTION PHP PAGE </H1>
  <p>
  <?php
// include files:
// connection function
include('connect.php');

$dd = $_POST['mydropdown'];

// used fixed-width font
echo "<pre>\n";

// print ID (name)
echo "Albums of Artist: $dd\n";

// set format string
$fmt = "%40s\n";

// print header line
printf($fmt, "Album Name");

// Get person likes for
$r1 = mysql_query("SELECT Title FROM CD WHERE Artist = '$dd'");
echo($r1[0]);
// loop over courses, printing each one
while ($r = mysql_fetch_row($r1))
{ 
    printf($fmt,$r[0]);
    echo($r[0]);
}

// free result set
mysql_free_result($r1);

echo "</pre>\n";
 ?>
 </BODY>
 </HTML>

下拉菜单中的PHP / HTML查询

0 个答案: