Question

我有一个像这样的字符串

     str = '["username"] = "user";
     ["deepscan"] = "true";
     ["token"] = true;
     ["password"] = "krghfkghkfghf";
     ["uploadMethod"] = "JSON";
     ["serviceIsRunning"] = {};
     ["host"] = "sample.com";
     ["instance_ID"] = 405454058;'

我希望模式匹配["password"] =并让它只替换此实例中";' that would be '"krghfkghkfghf"之间的字符串。

Answer 1

local function replacePass(configstr, newpass)
    return configstr:gsub("(%[\"password\"%]%s*=%s*)%b\"\"", "%1\"" .. newpass .. "\"")
end

如果你的密码里面包含双引号，那将无法运作。

Answer 2

我也有同样的问题，如何替换以下密码？

"password" : "krghfkghkfghf"

用模式替换Lua中的子字符串

2 个答案: