我有一个方法可以计算出具有最高组合值的3D数组元素。我有3个嵌套循环,我用来通过我的数组,并且在满足某些条件时我想改变变量。但是没有使用任何变量。如果int y
超过int m
,我会将sum
和total
更改为for循环的任何迭代。
感谢。这是我的代码:
public void wettestMonth(){
double sum = 0;
double total = 0;
int y = 0;
int m = 0;
//cycle through each year and month
for(int i = 0; i < 34; i++){
for(int j = 0; j < 12; j++){
//reset the current month to 0 after each month has been cycled through
sum = 0;
for(int k = 0; k < 31; k++){
//only add the record if the current entry is not null (-99.99)
if(sortedData[i][j][k] != -99.99){
sum += sortedData[i][j][k];
}
//if the current month is wetter than the wettest one, make the current month the new wettest one
if(sum > total){
total = sum;
y = i;
m = j;
}
}
}
}
JOptionPane.showMessageDialog(null, "The wettest month on record was " +m +y, "Wettest Month.", JOptionPane.PLAIN_MESSAGE);
}
编辑,我只是使用while循环重新构建它,而我在问题行if(sortedData[i][j][k] != -99.99)
编辑2,这是我声明并初始化sortedData[][][]
public class GetData {
//initialises an array that holds 34 years, each with 12 months, each of which has 31 entries for reach day
public double[][][] sortedData = new double[34][12][31];
//initialises a new scanner named rainFile
private Scanner rainFile;
//method for opening the file
public void openFile() {
try{
//as the input for the scanner we use the rainfall file
rainFile = new Scanner(new File("C:\\\\Users\\\\admin\\\\Documents\\\\NetBeansProjects\\\\110_term3\\\\WeatherDataFiles\\\\rainfall.txt"));
}
catch(Exception e){
//if no file has been found a JOptionPane will display an error message telling the user to double-check the file path
JOptionPane.showMessageDialog(null, "Check the file path is correct.", "No file found!", JOptionPane.ERROR_MESSAGE);
}
}
//method for reading the file
public void readFile(){
//ignore the first 3 lines in the data file
String dump1 = rainFile.nextLine();
String dump2 = rainFile.nextLine();
String dump3 = rainFile.nextLine();
//these nested for loops will dictate the current index of sortedData
for(int i = 0; i < 34; i++){
for(int j = 0; j < 12; j++){
//ignores the year and month at the start of each line
String dump4 = rainFile.next();
String dump5 = rainFile.next();
//this final nested for loop dictates the final index of sortedData
for(int k = 0; k < 31; k++){
//asigns the current value of scanner rainFile to String a
String a = rainFile.next();
//converts the String a to a double type and then assigns it to the current index of sortedData
double dbl = Double.parseDouble(a);
sortedData[i][j][k] = dbl;
}
}
}
}
答案 0 :(得分:3)
您是否尝试过打印每个月的金额?
最明显的可能性是,由于错误的等式检查,您的总和总是小于0。
对于这一行,
sortedData[i][j][k] != -99.99
除非值恰好是-99.99回合,否则它将是真的。这可能是无意的。例如,如果您通过某种方式通过浮点数学构造值,则由于舍入错误,您很可能无法获得完全相同的值。此外,像这样使用奇怪的哨兵值是容易出错且可读性差的。如果可以的话,最好使用像NaN这样明显的哨兵值。
要查看问题,请考虑如果您的值略有不同会发生什么。比如,-99.99000001。然后在第一天之后,您已经有了负值。一个月后,总和将大约为-3099.69000031,远小于0.因为总和总是负数,所以它永远不会比原来的总数0好,所以最好永远不会更新。
您可能还希望在日循环之外移动更新检查。这部分看起来应该使用整个月的总和,但是你运行的是每月的每一天的部分总和。只要添加的值是非负的(但它们可能不是由于前面提到的错误),它实际上不会导致不正确的结果,但你仍然应该修复它。
if(sum > total){
total = sum;
y = i;
m = j;
}
答案 1 :(得分:0)
我的代码没有看错。
也许以下情况永远不会变为真实?
if(sortedData[i][j][k] != -99.99)
答案 2 :(得分:0)
仔细检查了已经提供的第一个代码片段,在我看来,如果检查for循环内部的大小,将for循环变量移动到决赛,你一直在做,添加了一些进一步的评论。
您可以尝试通过Eclipse调试运行swing应用程序,看看您在应用程序的每一行得到的结果是什么?
如果给出正确的输入3D数组,它会发挥作用))
/**
* This method calculates the wettest month during the certain period of time.
*/
public void wettestMonth(){
double sum = 0;
double total = 0;
int y = 0;
int m = 0;
final int numberOfYearsToCycleThrough = 34;
final int numberOfMonthsToCycleThrough = 12;
//cycle through each year and month
for (int i = 0; i < numberOfYearsToCycleThrough; i++) {
for (int j = 0; j < numberOfMonthsToCycleThrough; j++) {
sum = 0;
for (int k = 0; k < 31; k++){
//only add the record if the current entry is not null (-99.99)
if (sortedData[i][j][k] != null && sortedData[i][j][k] != -99.99) {
sum += sortedData[i][j][k];
}
}
//if the current month is wetter than the wettest one, make the current month the new wettest one
if (sum > total) {
total = sum;
y = i;
m = j;
}
}
}
JOptionPane.showMessageDialog(null, "The wettest month on record was " +m +y, "Wettest Month.", JOptionPane.PLAIN_MESSAGE);
}