Question

我有一个表格，用户输入或选择表格如下的值

<form id="search_photos" action="photo_result.php" method="get">
<select name="Photographer_id" id="Photographer_id"   style="height:23px; border:1px solid Silver;">
    <option selected="selected" value="x">Any Photographer_id</option>
    <option value="John">John</option>
    <option value="Fred">Fred</option>
    <option value="Joseph">Joseph</option>
</select>
<select name="Photographer_id" id="Photographer_id"   style="height:23px; border:1px solid Silver;">
    <option selected="selected" value="x">Any Photographer_id</option>
    <option value="1">1</option>
    <option value="2">2</option>
    <option value="3">3</option>
</select>
<select name="images" id="images"   style="height:23px; border:1px solid Silver;">
    <option selected="selected" value="x">All Images</option>
    <option value="0">None</option>
    <option value="a">Image a</option>
    <option value="b">Image b </option>
    <option value="c">Image c </option>
</select>
    <select name="images_id" id="images_id"   style="height:23px; border:1px solid Silver;">
    <option selected="selected" value="x">All Images</option>
    <option value="0">None</option>
    <option value="1">1</option>
    <option value="2">2</option>
    <option value="3">3</option>
</select>
<input name="Submit" value="Search Now &gt;" id="Submit" class="Adv1_Filter_Button" type="submit">

然后抓取表单结果的search_photo.php脚本过滤用户输入的值，如下所示

$xml = simplexml_load_file("photo.xml");

for ($i = 0; $i < count($xml); $i++) {  

    if (isset($_GET["LocationName"])) {
        $photographer_id = $_GET["LocationName"];
    }

    $result = $xml->xpath('/root/area[photographer_id="' . $photographer_id . '"]  ');
}

if(isset($_GET["Photographer"])) {
    $photographer = $_GET["Photographer"];
} 

$result = $xml->xpath('/root/area[photographer_id="' . $photographer_id . '"]  ');

if(isset($_GET["images"])) {
    $image = $_GET["images"];
}

echo $photographer_id;
echo $photographer;
echo $image;
var_dump ($result);

第一个XPATH传递中的$result是正确的，如果我设置的所有内容都是'photographer_id'，然后我尝试$result = $xml->xpath('/root/area[photographer_id="' . $photographer_id . '"] | /root/area[photographer="' . $photographer . '"]');并选择1和fred然后我得到当它应该是一个空数组时，所有四个数组的结果可以建议如何纠正这个错误。抱歉michi这里是XML文件

 <?xml version="1.0" encoding="UTF-8"?>
  <root>
   <area>
    <photographer_id>1</photographer_id>
    <photographer>John</photographer>
    <image>a</image>
    <image_id>1</image_id>
   </area>
   <area>
    <photographer_id>1</photographer_id>
    <photographer>John</photographer>
    <image>b</image>
    <image_id>2</image_id>
   </area>
   <area>
    <photographer_id>1</photographer_id>
    <photographer>John</photographer>
    <image>c</image>
    <image_id>3</image_id>
   </area>
   <area>
    <photographer_id>2</photographer_id>
    <photographer>Fred</photographer>
    <image>a</image>
    <image_id>4</image_id>
   </area>
   <area>
    <photographer_id>3</photographer_id>
    <photographer>Joseph</photographer>
    <image>a</image>
    <image_id>5</image_id>
   </area>
  </root>

这会有所帮助，但最终的XML文件会比这更大。

Answer 1

这是一种方法：
（1）从表单中获取过滤器值并为xpath构建查询字符串：

$fields = array( // fieldname => value for "all"
    'photographer_id' => '',
    'photographer' => 'x',
    'image' => '0');

foreach ($fields as $fieldname => $fieldvalue)
    if (isset($_GET[$fieldname]) && trim($_GET[$fieldname]) != $fieldvalue)
    $query[] = "$fieldname = '$_GET[$fieldname]'";

if (isset($query)) 
    $query = "[" . implode(' or ', $query) . "]"; else $query = "";

（2）使用xpath过滤XML并显示所选节点

$xml = simplexml_load_string($x); // assume XML in $x
$results = $xml->xpath("area$query");

foreach ($results as $result) 
    echo "image $result->image by $result->photographer ($result->photographer_id)<br />";

看到它有效：http://codepad.viper-7.com/ciboJg

Answer 2

不确定你想要什么，因为你的问题不太清楚。即便如此，我coded a little snippet向您展示了如何使用XPath条件来检索表单上给定选择所需的area节点。

只需将$examples数组中的值视为表单上提交的可能值。

<?php
$xml = <<<XML
<?xml version="1.0" encoding="UTF-8"?>
<root>
    <area>
        <photographer_id>1</photographer_id>
        <photographer>John</photographer>
        <image>a</image>
    </area>
    <area>
        <photographer_id>1</photographer_id>
        <photographer>John</photographer>
        <image>b</image>
    </area>
    <area>
        <photographer_id>1</photographer_id>
        <photographer>John</photographer>
        <image>c</image>
    </area>
    <area>
        <photographer_id>2</photographer_id>
        <photographer>Fred</photographer>
        <image>a</image>
    </area>
</root>
XML;

$sxe = new SimpleXMLElement($xml);

$examples = array(
    array('id' => 1, 'name' => 'John'),
    array('name' => 'Fred'),
    array('id' => 1, 'name' => 'Fred'),
);

foreach ($examples as $example) {
    $conditions = array();

    if (!empty($example['id'])) {
        $conditions[] = "photographer_id = {$example['id']}";
    }

    if (!empty($example['name'])) {
        $conditions[] = "photographer = '{$example['name']}'";
    }

    $xpath_condition = implode(' and ', $conditions);
    echo "{$xpath_condition}\n";
    $area = $sxe->xpath("//area[{$xpath_condition}]");

    print_r($area);
}

输出：

photographer_id = 1 and photographer = 'John'
Array
(
    [0] => SimpleXMLElement Object
        (
            [photographer_id] => 1
            [photographer] => John
            [image] => a
        )

    [1] => SimpleXMLElement Object
        (
            [photographer_id] => 1
            [photographer] => John
            [image] => b
        )

    [2] => SimpleXMLElement Object
        (
            [photographer_id] => 1
            [photographer] => John
            [image] => c
        )
)
photographer = 'Fred'
Array
(
    [0] => SimpleXMLElement Object
        (
            [photographer_id] => 2
            [photographer] => Fred
            [image] => a
        )
)
photographer_id = 1 and photographer = 'Fred'
Array
(
)

Answer 3

你有一个长篇大论的simillar问题，我已经从那里采纳了这个想法并提出了这个我希望它有所帮助

<?php

$ xml = simplexml_load_file（“photo.xml”）;

for（$ i = 0; $ i＆lt; count（$ xml）; $ i ++）{

if(isset($_GET["LocationName"]))
{
    $photographer_id = $_GET["LocationName"];
}

$result = $xml->xpath('/root/area[photographer_id="' . $photographer_id . '"]  ');
}


if(isset($_GET["photographer"]))
{
    $photographer = $_GET["photographer"];
} 

if(isset($_GET["images"]))
{
    $image = $_GET["images"];

    //$result = $xml->xpath('/root/area[photographer_id="' . $photographer_id . '"] and /root/area[photographer="' . $photographer . '"]');

}

//echo $photographer_id;
//echo $photographer;
//echo $image;

$filteredResult = array();

foreach($result as $obj){
    if(in_array($photographer, (array)$obj) == 1 || $photographer == 'x'){ 
        if(in_array($image, (array)$obj) || $image == 'x'){
            array_push($filteredResult, $obj);
        }
    }
}

foreach($filteredResult as &$obj){
    //how to access values in the object
    echo $obj->{'photographer'};
    echo $obj->{'image'};
}
echo $obj->{'image'};

    ?>

最后一个回应应该给你一些指示

XPATH方法，用于使用PHP从XML文件重新调整多个动态结果

3 个答案:

输出：