Question

我正在编写一个PowerShell脚本，为用户提供了许多选项供您选择。选择一个选项后，将执行一项功能，并将用户返回原始菜单。

在下面的代码中，为用户提供选项，并执行功能，但完成后，脚本就会结束。我想要的是在函数的末尾返回到原始用户菜单。谁能告诉我怎么做？谢谢！

function firstFunction {
    Write-Host "You chose option 1"
    return
}

Write-Host "Welcome"

[int]$userMenuChoice = 0
while ( $userMenuChoice -lt 1 -or $userMenuChoice -gt 4){
    Write-Host "1. Menu Option 1"
    Write-Host "2. Menu Option 2"
    Write-Host "3. Menu Option 3"
    Write-Host "4. Quit and Exit"

[int]$userMenuChoice = Read-Host "Please choose an option"}
switch ($userMenuChoice) {
    1{firstFunction}
    2{Write-Host "You chose option 2"}
    3{Write-Host "You chose option 3"}
default {Write-Host "Nothing selected"}
}

Answer 1

将菜单代码放入外部循环，除非$userMenuChoice为4，否则不会终止：

do {
  [int]$userMenuChoice = 0
  while ( $userMenuChoice -lt 1 -or $userMenuChoice -gt 4) {
    Write-Host "1. Menu Option 1"
    Write-Host "2. Menu Option 2"
    Write-Host "3. Menu Option 3"
    Write-Host "4. Quit and Exit"

    [int]$userMenuChoice = Read-Host "Please choose an option"

    switch ($userMenuChoice) {
      1{firstFunction}
      2{Write-Host "You chose option 2"}
      3{Write-Host "You chose option 3"}
      default {Write-Host "Nothing selected"}
    }
  }
} while ( $userMenuChoice -ne 4 )

如何在PowerShell中的函数末尾返回用户菜单

1 个答案: