Question

我有3个下拉列表我希望显示用户在选择某个功能或scrpt后会选择的内容，但它必须在脚本中

<?php
$resource_names = mysql_query("SELECT DISTINCT NAME FROM selections ORDER BY id ASC");
$names = array();
while($row = mysql_fetch_row($resource_names)){
    $names[] = $row[0]    
} 
$resource_surnames = mysql_query("SELECT DISTINCT SURNAME FROM selections ORDER BY id ASC"); 
$surnames = array();
while($row = mysql_fetch_row($resource_surnames)){
    $surnames[] = $row[0];
} 
$resource_emails   = mysql_query("SELECT DISTINCT EMAIL FROM selections ORDER BY id ASC");    
$emails = array();
while($row = mysql_fetch_row($resource_emails)){
    $emails[] = $row[0];
}
if(count($emails) <= 0 || count($surnames) <= 0 || count($emails) <= 0){
    echo 'No results have been found.';
} else {

    // Display form
    echo '<form name="form" method="post" action="test.php">';

    //Names dropdown:
    echo '<select name="id" id="names">';
    foreach($names as $name) echo "<option id='$name'>$name</option>";
    echo '</select>';

    //Surnames dropdown
    echo '<select name="id" id="surnames">';
    foreach($surnames as $surname) echo "<option id='$surname'>$surname</option>";
    echo '</select>';

    //Emails dropdown
    echo '<select name="id" id="emails">';
    foreach($emails as $email) echo "<option id='$email'>$email</option>";
    echo '</select>';

    echo "<button id='write_in_div'>Click me!</button>";

    echo '</form>';

}
?>

点击我时会调用write_in_div的东西！按钮是按下或任何其他可用于显示3选择用户选择的方法

输出应该类似于您选择1）名称2）姓氏和电子邮件

Answer 1

你的html中有一个错误选择每个选择具有相同的名称“id”，它们每个都需要是唯一的，这样你就可以检测到。

您需要检测用户是否已提交表单

if(isset($_POST["select_name"])) {
     echo $_POST["select_name"];
}

Answer 2

你的表格有一个很大的错误。在表单中，每个选择和输入必须具有唯一的名称。您需要此名称才能在PHP脚本中检索提交的值。

我想你有这个：

<?php
$resource_names = mysql_query("SELECT DISTINCT NAME FROM selections ORDER BY id ASC");
$names = array();
while($row = mysql_fetch_row($resource_names)){
    $names[] = $row[0]    
} 
$resource_surnames = mysql_query("SELECT DISTINCT SURNAME FROM selections ORDER BY id ASC"); 
$surnames = array();
while($row = mysql_fetch_row($resource_surnames)){
    $surnames[] = $row[0];
} 
$resource_emails   = mysql_query("SELECT DISTINCT EMAIL FROM selections ORDER BY id     ASC");    
$emails = array();
while($row = mysql_fetch_row($resource_emails)){
    $emails[] = $row[0];
}
if(count($emails) <= 0 || count($surnames) <= 0 || count($emails) <= 0){
    echo 'No results have been found.';
} else {

// Display form
echo '<form method="post" action="test.php">';

//Names dropdown:
echo '<select name="names">';
foreach($names as $name) echo "<option id='$name'>$name</option>";
echo '</select>';

//Surnames dropdown
echo '<select name="surnames">';
foreach($surnames as $surname) echo "<option id='$surname'>$surname</option>";
echo '</select>';

//Emails dropdown
echo '<select name="emails">';
foreach($emails as $email) echo "<option id='$email'>$email</option>";
echo '</select>';

echo '<button id="write_in_div">Click me!</button>';

echo '</form>';
}

提交表单时，test.php将包含发布的数据：$ _REQUEST ['names']，$ _REQUEST ['surnames']和$ _REQUEST ['emails']。

你必须检查一下vars的内容并打印它们，如果不是null。

注1：？＆gt;在文件的末尾没用。

注意2：在编写html文件时要小心'和'.html属性的值是用“，而不是”写的。

用户选择3选项后显示下拉值

2 个答案: