当我正在运行测试时@Autowired正在运行,但当我运行Web应用程序并尝试获取数据时,它会抛出空指针异常。
这是我的控制器
此BuyerRepo始终为空
import com.retail.exception.InvalidIdException;
import com.retail.model.Buyer;
import com.retail.repository.BuyerRepo;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
@Path("/buyer")
@Component
public class BuyerController {
@Autowired
private BuyerRepo buyerRepo;
@GET
@Produces("application/json")
public Buyer searchFields() throws InvalidIdException {
String buyerId = "51";
Buyer buyer;
try {
buyer = buyerRepo.getBuyer(Long.parseLong(buyerId));
} catch (NumberFormatException e) {
buyer = buyerRepo.getBuyer(buyerId);
}
return buyer;
}
}
在存储库实体管理器中始终为空
这是buyerRepository
import com.retail.exception.InvalidIdException;
import com.retail.model.Buyer;
import org.springframework.stereotype.Repository;
import javax.persistence.NoResultException;
@Repository
public class BuyerRepo extends AbstractRepository {
public Buyer getBuyer(String buyerName) throws InvalidIdException {
javax.persistence.Query buyerId = entityManager.createNativeQuery("select b.buyer_id from buyer b where b.name = :name").setParameter("name", buyerName);
Integer id;
try {
id = (Integer) buyerId.getSingleResult();
} catch (NoResultException e) {
return null;
}
return getBuyer(id);
}
public Buyer getBuyer(long buyerId) throws InvalidIdException {
Buyer buyer = entityManager.find(Buyer.class, buyerId);
if (buyer == null) throw new InvalidIdException("Invalid Article ID");
return buyer;
}
}
这是applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<context:annotation-config/>
<context:component-scan base-package="com.retail"/>
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.postgresql.Driver"/>
<property name="url" value="jdbc:postgresql://localhost/retail"/>
<property name="username" value="retail_user"/>
<property name="password" value="password"/>
</bean>
<bean id="entityManagerOne" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="packagesToScan" value="com.retail"/>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="databasePlatform" value="org.hibernate.dialect.PostgreSQLDialect"/>
</bean>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerOne"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
</beans>
这是servlet-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<mvc:annotation-driven />
<context:annotation-config />
<context:component-scan base-package="com.retail" />
</beans>
这是web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd">
<servlet>
<servlet-name>retail</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.retail.web</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>retail</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:applicationContext.xml
/WEB-INF/servlet-context.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>/WEB-INF/views/index.jsp</welcome-file>
</welcome-file-list>
</web-app>
答案 0 :(得分:1)
您可以尝试使用SpringServlet而不是jersey提供的servlet容器来实现Jersey-Spring集成。
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
此课程的文档说明:
用于使用Spring集成部署根资源类的servlet或过滤器。 该类扩展了ServletContainer并使用基于Spring的方式启动WebApplication IoCComponentProviderFactory,SpringComponentProviderFactory,这样的资源和提供者的实例 可以获得Spring声明和管理的类。 使用基于XML的配置或基于自动线路的配置声明的Spring bean类将是 如果此类是根资源类或提供程序类,则自动注册。没有必要提供 用于在web.xml中声明类的初始化参数,除非Spring-managed和Jersey-的混合 托管类是必需的。 servlet支持子applicationContexts的配置,请参阅CONTEXT_CONFIG_LOCATION。
答案 1 :(得分:1)
我遇到过这种情况, 你需要添加一些jar文件
gradle项目:
compile group: 'org.glassfish.jersey.ext', name: 'jersey-spring3', version: '2.22.2'
maven项目:
<dependency>
<groupId>org.glassfish.jersey.ext</groupId>
<artifactId>jersey-spring3</artifactId>
<version>2.22.2</version>
</dependency>
另一个解决方案是web.xml文件:
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>cn.ice</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
答案 2 :(得分:0)
您必须连接接口而不是类。所以有两种方式:
让BuyerRepo实现一个界面
使用@Inject或@Resource代替@Autowired
答案 3 :(得分:0)
看起来你的买家雷波没有公共制定者。它也不可能通过构造函数设置它。如何为它编写一个setter并将@Autowired注释放在setter上。像这样:
@Repository
public class BuyerRepo extends AbstractRepository {
private BuyerRepo buyerRepo;
@Autowired
public void setBuyerRepo(BuyerRepo buyerRepo)
{
this.buyerRepo = buyerRepo;
}
//...Other code is omitted.
}