Question

我希望javascript代码检查我的输入文字是否为特定格式AS0301-12345

<apex:inputText id="searchText" value="{!searchText}" onmousemove="checkingstring(this)"/>

<script>
function checkingstring(searchText){
var pattern = "([a-zA-Z](2)[0-9](4)-[0-9](5))";  /// is it correct
var regexp = new System.Text.RegularExpressions.Regex(pattern);
var userInput = "(123) 555-1243";
if (!regexp.IsMatch($component.searchText))
 {
  alert("The syntax is always as follows: AANNNN-NNNNN (A= Alpha/Letter; N= Number) i.e.FL0301-12345</b>");  

}
}
</script>

Answer 1

你的JS函数看起来应该更像这样：

function checkingstring(inputElem) {
  var regex = /^[A-Z]{2}[0-9]{4}-[0-9]{5}$/i;
  var searchText = inputElem.value;
  if (searchText.length && !regex.test(searchText)) {
    alert('The syntax is always as follows: AANNNN-NNNNN \n' +
          '(A: Alpha/Letter; N: Number), e.g. FL0301-12345');
  }
}

您可能还应该将onmousemove更改为更有意义的内容，例如onblur 请看一下 short demo 。

Answer 2

我就是这样做的。有很多功能可以用来缩写。将onMouseMove更改为onChange，以便在鼠标移动时检查它，而不是检查searchText的编辑何时完成。

<apex:inputText id="searchText" value="{!searchText}" onChange="checkingstring(this)"/>

<script>
function checkingstring(searchText){
    var regexp = /^[A-Z]{2}\d{4}-\d{5}$/i; //AANNNN-NNNNN A = Capital N = Number
    if (!regexp.exec(searchText.value)) {
        alert("The syntax is always as follows: AANNNN-NNNNN (A= Alpha/Letter; N= Number) i.e.FL0301-12345</b>");  
    }
}
</script>

从w3schools js regexp页面获得了一些想法。

javascript以这种格式检查字符串

2 个答案: