如何在Tkinter的子窗口中插入树视图

Question

亲爱的所有我一直在尝试使用Tkinter在子窗口中插入树视图，但由于我不知道如何将它们放在一起，因此它非常复杂。非常感谢你提前！ Héctor

这是我到目前为止所做的：

import Tkinter
from Tkinter import *
import tkFont
import ttk 
root= Tk()

class McListBox(object):

    def __init__(self):
        self.tree = None
        self._setup_widgets()
        self._build_tree()

    def _setup_widgets(self):
        s = """
        """
        msg = ttk.Label(wraplength="4i", justify="right", anchor="n",
            padding=(6, 6, 6, 6, 6 ,6), text=s)
        msg.pack(fill='x')
        container = ttk.Frame()
        container.pack(fill='both', expand=True)
        self.tree = ttk.Treeview(columns=element_header, show="headings")
        vsb = ttk.Scrollbar(orient="vertical", command=self.tree.yview)
        hsb = ttk.Scrollbar(orient="horizontal", command=self.tree.xview)
        self.tree.configure(yscrollcommand=vsb.set, xscrollcommand=hsb.set)
        self.tree.grid(column=0, row=0, sticky='nsew', in_=container)
        vsb.grid(column=1, row=0, sticky='ns', in_=container)
        hsb.grid(column=0, row=1, sticky='ew', in_=container)
        container.grid_columnconfigure(0, weight=1)
        container.grid_rowconfigure(0, weight=1)

    def _build_tree(self):
        for col in element_header:
            self.tree.heading(col, text=col.title(),
                command=lambda c=col: sortby(self.tree, c, 0))
            self.tree.column(col, width=tkFont.Font().measure(col.title()))
        for item in element_list:
            self.tree.insert('', 'end', values=item)
            for ix, val in enumerate(item):
                col_w = tkFont.Font().measure(val)
                if self.tree.column(element_header[ix], width=None) < col_w:
                    self.tree.column(element_header[ix], width=col_w)
def isnumeric(s):
    for c in s:
        if c in "0000123456789000-.":
            numeric = True
        else:
            return False
    return numeric

def change_numeric(data):
    new_data = []
    if isnumeric(data[0][0]):
        for child, col in data:
            new_data.append((float(child), col))
        return new_data
    return data
def sortby(tree, col, descending):
    data = [(tree.set(child, col), child) for child in tree.get_children('')]
    data =  change_numeric(data)
    data.sort(reverse=descending)
    for ix, item in enumerate(data):
        tree.move(item[1], '', ix)
    tree.heading(col,
        command=lambda col=col: sortby(tree, col, int(not descending)))
element_header = ["Device", "Type", "LETs Threshold (L0)"]
element_list =  [('93L422', 'Bipolar', '0.6')]

mc_listbox = McListBox()

def Child_Window():
    win2 = Toplevel()
    message = "This is the child window"
    Label(win2, text=message).pack()
    Button(win2, text='OK', command=win2.destroy).pack()
Button(root, text='Bring up Message', command=Child_Window).pack()
root.mainloop()

Answer 1

应该使用父窗口作为第一个参数构造Treeview。我更改了Child_Window方法，以便显示非常简单的树。您现在可以轻松地将树调整为我的示例。我还建议以所有方法都包含在McListBox类中的方式重构代码。我使用了包几何管理器而不是网格管理器。这是我的例子：

def Child_Window():
    win2 = Toplevel()
    message = "This is the child window"
    Label(win2, text=message).pack()
    element_header=['1st','2nd','3rd']
    treeScroll = ttk.Scrollbar(win2)
    treeScroll.pack(side=RIGHT, fill=Y)
    tree = ttk.Treeview(win2,columns=element_header, show="headings", yscrollcommand = treeScroll)
    tree.heading("1st", text="1st")
    tree.pack(side=LEFT, fill=BOTH)
    treeScroll.config(command=tree.yview)

在与Hector讨论之后，我决定粘贴所有修改后的类，它们应该像所需的那样工作。顺便说一句，我重构它，以便所有函数和变量都是类的成员。适用于Python 2.7.5。

import Tkinter 
from Tkinter import *
import tkFont
import ttk

class ModifiedMcListBox(object):

    def __init__(self):
        self.root= Tk()
        self.tree = None
        self.element_header = ["Device", "Type", "LETs Threshold (L0)"]
        self.element_list =  [('93L422', 'Bipolar', '0.6')]
        self._setup_widgets()
        self._build_tree()
        self.root.mainloop()

    def _setup_widgets(self):
        s = """
        """
        msg = ttk.Label(wraplength="4i", justify="right", anchor="n",
            padding=(6, 6, 6, 6, 6 ,6), text=s)
        msg.pack(fill='x')
        container = ttk.Frame()
        container.pack(fill='both', expand=True)
        self.tree = ttk.Treeview(columns=self.element_header, show="headings")
        vsb = ttk.Scrollbar(orient="vertical", command=self.tree.yview)
        hsb = ttk.Scrollbar(orient="horizontal", command=self.tree.xview)
        self.tree.configure(yscrollcommand=vsb.set, xscrollcommand=hsb.set)
        self.tree.grid(column=0, row=0, sticky='nsew', in_=container)
        vsb.grid(column=1, row=0, sticky='ns', in_=container)
        hsb.grid(column=0, row=1, sticky='ew', in_=container)
        container.grid_columnconfigure(0, weight=1)
        container.grid_rowconfigure(0, weight=1)
        Button(self.root, text='Bring up Message', command=self.Child_Window).pack()

    def _build_tree(self):
        for col in self.element_header:
            self.tree.heading(col, text=col.title(),
                command=lambda c=col: self.sortby(self.tree, c, 0))
            self.tree.column(col, width=tkFont.Font().measure(col.title()))
        for item in self.element_list:
            self.tree.insert('', 'end', values=item)
            for ix, val in enumerate(item):
                col_w = tkFont.Font().measure(val)
                if self.tree.column(self.element_header[ix], width=None) < col_w:
                    self.tree.column(self.element_header[ix], width=col_w)

    def isnumeric(self,s):
        for c in s:
            if c in "0000123456789000-.":
                numeric = True
            else:
                return False
        return numeric

    def change_numeric(self,data):
        new_data = []
        if self.isnumeric(data[0][0]):
            for child, col in data:
                new_data.append((float(child), col))
            return new_data
        return data

    def sortby(self,tree, col, descending):
        data = [(tree.set(child, col), child) for child in tree.get_children('')]
        data = self.change_numeric(data)
        data.sort(reverse=descending)
        for ix, item in enumerate(data):
            tree.move(item[1], '', ix)
        tree.heading(col,
            command=lambda col=col: sortby(tree, col, int(not descending)))

    def Child_Window(self):
        win2 = Toplevel()
        message = "This is the child window"
        Label(win2, text=message).pack()
        new_element_header=['1st','2nd','3rd']
        treeScroll = ttk.Scrollbar(win2)
        treeScroll.pack(side=RIGHT, fill=Y)
        tree = ttk.Treeview(win2,columns=new_element_header, show="headings", yscrollcommand = treeScroll)
        tree.heading("1st", text="1st")
        tree.heading("2nd", text="2nd")
        tree.heading("3rd", text="3rd")
        tree.pack(side=LEFT, fill=BOTH)
        treeScroll.config(command=tree.yview)

mc_listbox = ModifiedMcListBox()

Answer 2

解决方案很简单：每个小部件都将另一个小部件作为其第一个参数，此参数定义新小部件的父级。默认情况下，当您使用pack，grid或place时，新窗口小部件将显示在专利窗口小部件中。这真的是你需要知道的全部。

因此，如果您希望self.tree位于win2中，则win2必须*作为第一个参数提供给treeview构造函数。

请注意，您无法在一个窗口中创建窗口小部件，然后将其移动到另一个窗口（“窗口”定义为“Tk或Toplevel的实例”。窗口及其父窗口必须与祖先共享最顶层的窗口小部件。

*“必须”有点过于强大，因为您可以将小部件显示在小组件中，而不是直接父级。我不认为这与你在这里要做的事情有关，所以我不会详细说明避免混淆。